Answer:
r = -12cos(θ)
Step-by-step explanation:
The usual translation can be used:
Putting these relationships into the formula, we have ...
(r·cos(θ) +6)² +(r·sin(θ))² = 36
r²·cos(θ)² +12r·cos(θ) +36 +r²·sin(θ)² = 36
r² +12r·cos(θ) = 0 . . . . subtract 36, use the trig identity cos²+sin²=1
r(r +12cos(θ)) = 0
This has two solutions for r:
r = 0 . . . . . . . . a point at the origin
r = -12cos(θ) . . . the circle of interest
Answer:
False cuase 5 is in thousands
A) x < -12
sorry can't do b
Answer:
(a) - 25 boxes per dollar
(b) - 20 boxes per dollar
Step-by-step explanation:
Given that,
Consumer's willing to buy boxes of nails at p dollars per box:
N(p) = 80 - 5p^{2}
(a) Change in price from $2 to $3.
N(2) = 80 - 5(2)^{2}
= 80 - 20
= 60
N(3) = 80 - 5(3)^{2}
= 80 - 45
= 35
Therefore, the average rate of change of demand is
= [N(3) - N(2)] ÷ (3 - 2)
= 35 - 60
= - 25 boxes per dollar.
(b) N(p) = 80 - 5p^{2}
Now, differentiating the above function with respect to p,
N'(p) = -10p
Therefore, the instantaneous rate of change of demand when the price is $2 is calculated as follows:
N'(p) = -10p
N'(2) = -10 × 2
= -20 boxes per dollar
9514 1404 393
Answer:
18 weeks
Step-by-step explanation:
We are given the (time, population) pairs (0, 5) and (7, 47). With these values, we can use the two-point form of the equation of a line to write the equation of the linear model.
p = (p2 -p1)/(t2 -t1)(t -t1) +p1
p = (47 -5)/(7 -0)(t -0) +5
p = 6t +5 . . . . . the linear model matching the given points.
For p = 113, the time (number of weeks) is ...
113 = 6t +5
108 = 6t . . . . . . subtract 5
18 = t . . . . . . . . . divide by 6
After 18 weeks, the beetle population will reach 113.
