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tatyana61 [14]
3 years ago
10

A population of beetles are growing according to a linear growth model. The initial population (week 0) is

Mathematics
1 answer:
klemol [59]3 years ago
6 0

9514 1404 393

Answer:

  18 weeks

Step-by-step explanation:

We are given the (time, population) pairs (0, 5) and (7, 47). With these values, we can use the two-point form of the equation of a line to write the equation of the linear model.

  p = (p2 -p1)/(t2 -t1)(t -t1) +p1

  p = (47 -5)/(7 -0)(t -0) +5

  p = 6t +5 . . . . . the linear model matching the given points.

For p = 113, the time (number of weeks) is ...

  113 = 6t +5

  108 = 6t . . . . . . subtract 5

  18 = t . . . . . . . . . divide by 6

After 18 weeks, the beetle population will reach 113.

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Factor completely 4x2 − 8x + 4.
olga nikolaevna [1]

<u>Given </u><u>:</u><u>-</u><u> </u>

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<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u>

  • To find the factorised form .

<u>Answer</u><u> </u><u>:</u><u>-</u><u> </u>

Taking the given expression,

→ 4x² - 8x + 4

→ 4x² - 4x -4x + 4

→ 4x ( x - 1 ) -4( x -1)

→ (4x - 4)(x-1)

<u>Hence </u><u>the</u><u> </u><u>required</u><u> answer</u><u> is</u><u> </u><u>(</u><u>4</u><u>x</u><u> </u><u>-</u><u> </u><u>4</u><u>)</u><u>(</u><u> </u><u>x </u><u>-</u><u> </u><u>1</u><u>)</u><u> </u><u>.</u>

4 0
3 years ago
Write an equation of the line in point slope form, that passes through the two given points
Anika [276]

Answer:

  y -15 = -3(x +2)

Step-by-step explanation:

The slope will be ...

  m = (y2 -y1)/(x2 -x1)

  m = (-18 -15)/(9 -(-2)) = -33/11 = -3

Point-slope form is ...

  y -y1 = m(x -x1) . . . . . line with slope m through point (x1, y1)

Using the first point, the equation is ...

  y -15 = -3(x +2)

4 0
3 years ago
Plz answer. What is the sum? 3x^2-2x-1/x-5 + -2x^2+x-5/x-5
IrinaVladis [17]

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
9. Use the​ compound-interest formula to find the account balance​ A, where P is​ principal, r is interest​ rate, n is number of
IceJOKER [234]

Interest on interest, or compound interest, is the adding of interest to the principal sum of a loan or deposit. The account balance after a period of 5 years will be $1.63634×10²⁰.

<h3>What is compound interest?</h3>

Interest on interest, or compound interest, is the adding of interest to the principal sum of a loan or deposit. It's the outcome of reinvesting interest rather than paying it out so that interest is received on the principal plus previously collected interest in the next quarter.

A = P(1 + \frac{r}{n})^{nt}

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

Given the principal amount is $12,385, the rate of interest is 7.5%, and the time period is daily. Therefore, the amount can be written as,

A = P(1 + \frac{r}{n})^{nt}\\\\A = \$12,385(1 + \frac{7.5}{365})^{(365 \times 5)}\\\\A = \$1.63634 \times 10^{20}

Hence, the account balance after a period of 5 years will be $1.63634×10²⁰.

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5 0
2 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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