Tell whether the following equation has one, zero, or infinitely many solutions.

Mathematics

1 answer:

kipiarov [429]3 years ago

3 0

Answer:

Option C: One solution

Step-by-step explanation:

5x + 6 = 2 + 3x

Subtract 3x from both sides;

2x + 6 = 2

Subtract 6 from both sides;

2x = -4

Divide both sides by 2;

x = -2

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Write the vertex form of the equation of the parabola which has a vertex of (0,0) and contains the point (2,-2)

Anettt [7]

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=a(x-{{ h}})^2+{{ k}}\qquad 
\begin{cases}
h=0\\
k=0
\end{cases}\implies y=a(x-0)^2+0
\\\\\\
y=ax^2\qquad 
\begin{cases}
x=2\\
y=-2
\end{cases}\implies -2=a2^2$

solve for "a", to get the coefficient, and then plug it back in the equation.

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4 years ago

The equations 9 x minus 10 y = 6, 8 x minus 10 y = negative 23, 9 x + 10 y = negative 16, and 8 x + 10 y = 13 are shown on the g

neonofarm [45]

Answer:

Step-by-step explanation:

The two equations are 8x-10y=-23 and 9x+10y=-16.

If you plug them both into a graphing calculator, you will see that the point where they cross (the solution) is (-2.3, 0.5).

The answer is A.

4 0

3 years ago

Read 2 more answers