X/3+7
co-efficient=1/3
how?
x/3 is also the same as x(1/3).
-6(2x - 4) = -6*(2x) -6*(-4) = -12x + 24
-(12x - 6) + 18 = -12x + 6 + 18 = -12x + 24
-3(4x - 3) + 15 = -3*(4x) -3*(-3) + 15 = -12x + 9 + 24 = -12x + 24
-4(3x + 6)
= -4*(3x) -4*(6) = -12x -24
All the expressions gave the same answer as -12x + 24, except for the last expression.
So, -4(3x + 6)
is not equivalent to the others.
Answer:
25.05 miles per week
Step-by-step explanation:
We know that,
1 mile = 1760 yards
⇒ 920 yards = 0.522 mile
1 week = 168 hour
We need to find ts speed in miles per week.
Speed = distance/time
So, the speed of the object is 25.05 miles per week.
C + 2c + 12 = 75
Combine like terms:
3c + 12 = 75
Subtract 12 to both sides:
3c = 63
Divide 3 to both sides:
c = 21
The expected activity time for the given statement is = 5.33
<h3>What time is the PERT network expected to be active?</h3>
The average amount of time required for an activity when it is repeatedly performed is known as the expected time. The weighted average of the three estimated times, i.e., the optimistic time, the most probable time, and the pessimistic time, is used in project management analysis to determine the expected time of activity.
<h3>The PERT system:</h3>
A network model called the Program Evaluation and Review Technique (PERT) allows for randomness in the timing of activity completion. PERT was created in the late 1950s again for a massively labor-intensive Polaris project for the US Navy. It might shorten a lot of time and cost needed to finish a project.
<h3>According to the given information:</h3>
optimistic = 2
most likely = 5
pessimistic = 10.
We will use the following formula to calculate the anticipated time for each activity in order to solve this problem:
Expected Time = (Optimistic Time + (4 x Most likely) + Pessimistic Time) / 6
Putting the values into formula:
= (2 + (4 x 5) + 10)/ 6
= (2 + 20 + 10) / 6
= 5.33
To know more about PERT network visit:
brainly.com/question/17464130
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