5 = 15/3
3 1/3 = 10/3
15/3 - 10/3 = 5/3
so 5-3 1/3 is either 5/3 or 1 2/3.
There are 72 tens in 720.
They will require between 18.42 and 31.58 minutes.
We want the middle 90%. The two probability values associated with this would be 0.95 and 0.05; this would leave 5% below and 5% above, giving us the middle 90%.
Using a z-table (http://www.z-table.com) we see that the z-score associated with an area to the left of 0.05 is between -1.64 and -1.65; since it is equally distant from both we will use -1.645.
The z-score associated with an area of the left of 0.95 is between 1.64 and 1.65; since it is equally distant from both we will use 1.645.
The formula for a z-score is
z = (X-μ)/σ
-1.645 = (X-25)/4
Multiplying by 4 on both sides,
-1.645(4) = X-25
-6.58 = X-25
Adding 25 to both sides,
-6.58+25 = X
18.42 = X
For the upper bound,
1.645 = (X-25)/4
Multiplying both sides by 4,
1.645(4) = X-25
6.58 = X-25
Adding 25 to both sides,
6.58+25 = X
31.58 = X
The times are between 18.42 and 31.58 minutes.
3/10 is 30%
30% + 17% = 47%
100% is our total animals
100% - 47% (Lions + Zebras) = 53% (Tigers)
So 53% are tigers.
Answer:
1,000cm
Step-by-step explanation:
I just did the practice. I got it right.
