A cookie factory puts 2/5 of a barrel of flour into each batch of cookies. How much flour will the factory use for 10 batches?

Pam needs 3 1/2 cups of sugar to make 50 cupcakes, a 5-pound bag of sugar costs $3.69. There are about 2 cups of sugar in a poun

Alja [10]

Answer:

$1.70

Step-by-step explanation:

3 0

2 years ago

Which property could be used to find the missing number?

LiRa [457]

–4 • (–6.2 + 5) = –4 • (-6.2) + (–4) • 5 it is the so called
distributive property
so the answer is
B.distributive property

7 0

3 years ago

The function shown below was created to track the different intervals of speed that an automobile travels over a period of 28 se

Ksenya-84 [330]

Answer:

1. The car is slowing down at a rate of 2.5mph/s

2. The greatest acceleration is 10 mph/s.

3. In the interval 4s to 16s the speed remains constant and has magnitude 25 mph.

Step-by-step explanation:

1. The deceleration of the car is from 16 seconds to 24 seconds is the slope $m$ of the graph from 16 to 24:

$m=\dfrac{\Delta speed }{\Delta time } = \dfrac{5-25}{24-16} =-2.5mph/s$

the negative sign indicates that it is deceleration.

2. The automobile experiences the greatest change in speed when the slope is greatest because that is when acceleration/deceleration is greatest.

From the graph we see that the greatest slope of the graph is between 28 and 24 seconds. The acceleration the interval is the slope $m$ :

$m= \dfrac{45-5}{28-24}= 10mph/s$

3. The automobile experiences no acceleration in the interval 4 s to 16 s—that's the graph is flat.

The speed of the automobile in that interval, as we see from the graph, is 25 mph.

7 0

3 years ago

Read 2 more answers

Can someone explain this differentiation question to me? I can differentiate but then I'm not sure what I am doing

weeeeeb [17]

note that gradient = $\frac{dy}{dx}$ at x = a

calculate $\frac{dy}{dx}$ for each pair of functions and compare gradient

(a)

$\frac{dy}{dx}$ = 2x and $\frac{dy}{dx}$ = - 1

at x = 4 : gradient = 8 and - 1 : 8 > - 1

(b)

$\frac{dy}{dx}$ = 2x + 3 and $\frac{dy}{dx}$ = - 2

at x = 2 : gradient = 7 and - 2 and 7 > - 2

(c)

$\frac{dy}{dx}$ = 4x + 13 and $\frac{dy}{dx}$ = 2

at x = - 7 : gradient = - 15 and 2 and 2 > - 15

(d)

$\frac{dy}{dx}$ = 6x - 5 and $\frac{dy}{dx}$ = 2x - 2

at x = - 1 : gradient = - 11 and - 4 and - 4 > - 11

(e)

y = √x = $x^{\frac{1}{2} }$

$\frac{dy}{dx}$ = 1/(2√x) and $\frac{dy}{dx}$ = 2

at x = 9 : gradient = $\frac{1}{6}$ and 2 and 2 > $\frac{1}{6}$

4 0

3 years ago

Two mechanics worked on the car the first mechanic work for five hours in a sec mechanic work for 15 hours together the tires a

FrozenT [24]

Answer:

Mechanic 1: $55 per hour

Mechanic 2: $105 per hour

Step-by-step explanation:

Given

Represent the rate of the first mechanic with x and the second with y.

So, we have:

$x + y = 160$

The total earnings is: $1850, so we have:

$5x + 15y = 1850$

Required

Determine the rate of each

The equations are:

$x + y = 160$ --- (1)

$5x + 15y = 1850$ --- (2)

Divide (2) through by 5

$x + 3y = 370$ --- (3)

Subtract (1) from (3)

$x - x + 3y - y = 370 - 160$

$2y = 210$

Divide through by 2

$y = \frac{210}{2}$

$y = 105$

Substitute 105 for y in (1)

$x + y = 160$

Make x the subject

$x = 160 - y$

Substitute 105 for y

$x = 160 - 105$

$x = 55$

Hence:

Mechanic 1: $55 per hour

Mechanic 2: $105 per hour

7 0

2 years ago