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2 years ago

Perimeter = 16x + 8 The length of the indicated side is

Mathematics

1 answer:

Dahasolnce [82]2 years ago

6 0

Answer:

Step-by-step explanation:

Because you need to substitute the variable first, multiply that and add 8.

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Timed please help :))

Sphinxa [80]

It's the first one :))

3 0

3 years ago

3x(x+5y)+2y(7x-y)+4(^2+2y)

aksik [14]

Answer:

Step-by- step :

6 0

3 years ago

Slope = 1/2 goes through (2,6)

Darina [25.2K]

I’m not sure what the question is but I’m just gonna assume that you need the equation: y=1/2x+5

3 0

2 years ago

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

5 0

3 years ago

How much interest is earned on a principle of $864.27 invested at an interest rate of 8% for 3 years? Round to the nearest cent

amid [387]

Answer:

the interest =20.74

whereas the total sum=8850(the sum is the nearest cent)

<h2>HOPE IT HELPS YOU</h2>

7 0

3 years ago