If 101 use 3/5 for his Artwork, then the space remaining for 102 is:
5/5 - 3/5 = 2/5 (since the whole wall represents 100% or 5/5 or 1)
If the given differential equation is
then multiply both sides by 
:
The left side is the derivative of a product,
![\dfrac{d}{dx}\left[\sin(x)y\right] = \sec^2(x)](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%3D%20%5Csec%5E2%28x%29)
Integrate both sides with respect to 
, recalling that 
:
![\displaystyle \int \frac{d}{dx}\left[\sin(x)y\right] \, dx = \int \sec^2(x) \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%5Cfrac%7Bd%7D%7Bdx%7D%5Cleft%5B%5Csin%28x%29y%5Cright%5D%20%5C%2C%20dx%20%3D%20%5Cint%20%5Csec%5E2%28x%29%20%5C%2C%20dx)
Solve for 
:
![\boxed{y = \sec(x) + C \csc(x)}which follows from [tex]\tan(x)=\frac{\sin(x)}{\cos(x)}](https://tex.z-dn.net/?f=%5Cboxed%7By%20%3D%20%5Csec%28x%29%20%2B%20C%20%5Ccsc%28x%29%7D%3C%2Fp%3E%3Cp%3Ewhich%20follows%20from%20%5Btex%5D%5Ctan%28x%29%3D%5Cfrac%7B%5Csin%28x%29%7D%7B%5Ccos%28x%29%7D)
.
19%
In the division, 60% are women and 100%-60% = 40% are men. And for this project, we have 15% of the women, or 15%*60% = 9% of the personal and 25% of the men or 25% * 40% = 10% of the personal working on the project. Therefore 9% + 10% = 19% of the division is working on the project.
Answer:
$180
Step-by-step explanation:
Interest for 1 year = 10% of $300
Interest for 6 years
= (10% × 6) of $300
= 60% of $300
= (60/100) × $300
= 60 × $3
= $180
So, he will earn $180 as interest in 6 years.
Answer:
It would be subtract the product of 2 and 4 from the product of 5 and 3, then add 5 because it’s parenthesis then you would multiply/devide then add/subtract whatever comes first
Step-by-step explanation:
5x3 - (2x4) + 5
5x3 - 8 + 5
15 - 8 + 5
7 + 5
12
(Hice los cálculos aquí en caso de que lo necesitaras)
