Given:
Endpoints of a segment are (0,0) and (27,27).
To find:
The points of trisection of the segment.
Solution:
Points of trisection means 2 points between the segment which divide the segment in 3 equal parts.
First point divide the segment in 1:2 and second point divide the segment in 2:1.
Section formula: If a point divides a line segment in m:n, then
Using section formula, the coordinates of first point are
Using section formula, the coordinates of first point are
Therefore, the points of trisection of the segment are (9,9) and (18,18).
Answer:
- quotient: 2x^2 +3x +7
- remainder: 20
Step-by-step explanation:
See the attachment.
At each step, the value being subtracted from the dividend is the product of the quotient term and the divisor. The quotient term is found by dividing the highest-degree term of the dividend by the highest degree term of the divisor (x).
When the dividend has a degree that is less than the degree of the divisor, we call that value (20) the remainder.
Answer:
Step-by-step explanation:
Since they are similar we can say
?/15=6/3
?=15(6)/3
?=30
Natural, Whole, and Integers. Hopefully I helped :)
The answer is definitely C because the words are very dark and creepy.
