Answer:
The answer is C.
Step-by-step explanation:
Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.
In this case, the initial postion is a platform 30ft above ground so h0=+30
The initial velocity is 38 ft/s straight up into the air so v0=+38
h(t)=-16t2+38t+30
When the object hits the ground, h=0.
h=-16t2+38t+30=0
Simplifying 8t2-19t-15=0
(8t+5)(t-3)=0
t=-5/8 or 3
As time cannot be -ve, t=3s. The answer is C.
<span>Use the slope intercept form y=<span><span>mx</span>+b, </span></span><span>where </span><span>m</span><span> is the slope and </span><span>b</span><span> is the y-intercept. So with saying that plug your problem in so y = -3x+3 so your answer would be m=-3 which is the slope.
~Hope this Helps! Good Luck!~
</span>
Your question does not make sense unless you can estimate but the answer would be 20.625
Work:
You have to multiply 5.50 to 3.75 because 45 is 75 percent of 60
The quotient if the equation is x3
1.= 6,391
2.=6,3910
3. = 6,39100
All you do is add the 0s at the end
