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3 years ago

Find the inverse of each function. g(x)= -4/x-1 - 1

Mathematics

1 answer:

vodomira [7]3 years ago

6 0

Answer:

g^-1(x)=-(4)/(x+2)

Step-by-step explanation:

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Prove that 1+cot²A=cosec²A

o-na [289]

Answer:

see explanation

Step-by-step explanation:

Consider the left side

1 + cot²A

= 1 + $\frac{cos^2A}{sin^2A}$

= $\frac{sin^2A+cos^2A}{sin^2A}$

= $\frac{1}{sin^2A}$

= cosec²A

= right side, thus proven

6 0

3 years ago

If 60 marks is 40% what is full marks

sukhopar [10]

150, I believe
"if 40% of a number is 60" (40/100) * x = 60 (.4) x = 60 [reduce or just write it this way] x = 60(.4) [multiply both sides by .40]

4 0

3 years ago

Abigail earned $10.26 for babysitting her cousin for 3 hours. How much did she earn in each hour?

scoundrel [369]

Divide total earned by number of hours:

10.26/3 = $3.42

She earned $3.42 per hour

5 0

3 years ago

Read 2 more answers

I need help can yall help

Svetach [21]

Answer:

360"

Step-by-step explanation:

Firstly, you need to be able to convert your feet to inches. Remember, one foot is equal to twelve inches. You multiply six inches by five feet and later multiply by twelve to convert to inches.

8 0

3 years ago

Read 2 more answers

A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the

Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

$D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{1}{455} = 0.0021$

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

$D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36$

Total outcomes:

12 peaches, from a set of 15. So

$T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455$

Probability:

$p = \frac{D}{T} = \frac{36}{455} = 0.0791$

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0

3 years ago