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2 years ago

Can someone please help me?

Mathematics

1 answer:

Feliz [49]2 years ago

7 0

Answer:

m<2 = 150

Step-by-step explanation:

m<2 = 150 because of alternate exterior angles

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Can someone help 12 points on the line

ANTONII [103]

Answer:

x=6

Step-by-step explanation:

We can write this as a ratio

x 9

---- = --------

10 15

Using cross products

15x = 10*9

15x = 90

Divide by 15

15x/15 = 90/15

x =6

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2 years ago

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The answer is Yes, Hope this helps !

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topjm [15]

Answer:

Step-by-step explanation:

The question has no division answer. That makes C and D incorrect.

A for some reason is backwards. It makes no sense to use that. You are left with B. The reason A or B is correct is that the burn of calories must get larger with an increase in hours.

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2 years ago

What’s the answer to this math question

Romashka [77]

Answer:

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Step-by-step explanation:

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2 years ago

Use the quadratic formula to solve the following equation -3x^2-x-3=0

tigry1 [53]

<u>Answer:</u>

$x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i$ are two roots of equation $-3 x^{2}-x-3=0$

<u>Solution:</u>

Need to solve given equation using quadratic formula.

$-3 x^{2}-x-3=0$

General form of quadratic equation is $a x^{2}+b x+c=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}$

Since $b^{2}-4 a c$ is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

$\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}$

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3 years ago