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3 years ago

Angle A is circumscribed about circle O. What is the measure of D?

Mathematics

1 answer:

Mariana [72]3 years ago

7 0

Answer:

m<D=50

Step-by-step explanation:

The reason is that ABOC is a quadrilateral, so its angle add up to 360*. Each of the tangent angles, <ABO and <ACO, has a measure of 90*.

m<ABO + m<ACO + m<A + m<O = 360

90 + 90 + m<A + m<O = 360

m<A + m<O = 180

80 + m<O =180

m<O = 100

If the measure of central angle <O is 100*, what is the measure of inscribed <D?

The measure of a central angle is equal to the measure of the arc it intercepts. If m<O = 100*, then m BC = 100.

The measure of an inscribed angle is half of the measure of the arc it intercepts. If m BC = 100*, then m<D = 50

m<D=50

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1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t

Mazyrski [523]

Answer:

Part (A): The required inequality is T < 35 or t >40.

Part (B): The correct option is C) Only x=7.

Part (C) |x+1|+5=2 has no solution; |4x+12|=0 has one solution; |3x|=9 has two solution.

Step-by-step explanation:

Consider the provided information.

Part (A)

Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer than 40°F is an unsafe food practice.

The union is written as A∪B or “A or B”.

The intersection of two sets is written as A∩B or “A and B”

We need to determine the inequalities represent the union of these improper storage.

That means we will use A∪B or “A or B”.

The improper storage temperatures is when temperature is less than 35°F or greater than 40°F.

Hence, the required inequality is T < 35 or t >40.

Part (B) 15| x-7|+4=10|x-7|+4

Solve the inequality as shown below:

Subtract 4 from both sides.

$15| x-7|+4-4=10|x-7|+4-4$

Subtract 10|x-7| from both sides

$5\left|x-7\right|=0\\\left|x-7\right|=0\\x=7$

Hence, the correct option is C) Only x=7.

Part (C) Match the solution,

$\left|x+1\right|+5=2$

Subtract 2 from both sides.

$\left|x+1\right|=-3$

Absolute value cannot be less than 0.

Hence, |x+1|+5=2 has no solution.

$|4x+12|=0$

$4x+12=0$

$x=-3$

Hence, |4x+12|=0 has one solution.

$|3x|=9$

$\mathrm{If}\:|u|\:=\:a,\:a>0\:\mathrm{then}\:u\:=\:a\:\quad \mathrm{or}\quad \:u\:=\:-a$

$3x=-9\quad \mathrm{or}\quad \:3x=9\\x=-3\quad \mathrm{or}\quad \:x=3$

Hence, |3x|=9 has two solution.

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3 years ago

Suppose y varies directly as x², and y = 160 when x = 4. Find y when x = 6.

labwork [276]

Finding the constant of proportionality :

y = kx²
160 = k(4)²
k = 10

Finding y when x = 6 :

y = 10(6)²
y = 10(36)
y = 360

The value of y is 360 when x = 6.

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2 years ago

A piling for a high-rise building is pushed by two bulldozers at exactly the same time. One bulldozer exerts a force of 1250 pou

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Murrr4er [49]

Answer:

Step-by-step explanation:

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