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OlgaM077 [116]
3 years ago
12

Help meee plss it’s timed !!

Mathematics
2 answers:
slamgirl [31]3 years ago
7 0

Answer:

i did it to its C

Step-by-step explanation:

mark me pls

mariarad [96]3 years ago
4 0

Answer:

D

Step-by-step explanation:

use Pythagoreans theorem to solve (a^2+b^2=c)

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Which is steeper: a road with a 12% grade or a road with a pitch of 1 in 8?
11Alexandr11 [23.1K]

Answer:

A road with a pitch of 1 in 8 is steeper.

Step-by-step explanation:

Let us convert these to the same units so that we can better compare them.

\frac{1}{8} = 0.125

0.125=12.5 %

As 12.5% is greater than 12%, the road with a pitch of 1 in 8 will be steeper.

7 0
4 years ago
The graph of the function g(x) is a transformation of the parent function f(x)=x².
Len [333]

Answer:

The answer is c)

Step-by-step explanation:

g(x)=x^2-4

3 0
3 years ago
A lot of 200 chips contain 5 that are defective. 8 are selected random with out replacement.
vaieri [72.5K]

<u>Answer:</u>

1 , \frac{1}{66}  (Answer)

<u>Step-by-step explanation:</u>

Since, 8 chips are selected at random and 5 are there defectives in the lot, So, at least (8 - 5) = 3 chosen chips will be non - defective.

So, P ( At least two of selected part is non defective ) = 1 .

P(first and second samples are defective)

= \frac{5 \times 4}{200 \times 199}

P ( first, second and third samples are defective)

= \frac{5 \times 4 \times 3}{200 \times 199 \times 198}

So,

\frac{{\textrm{Third sample is defective | first and second samples are defectives}}}

=\frac{{\textrm{  P ( first, second and third samples are defective)}}}{{\textrm{  P(first and second samples are defective) }}}

= \frac{3}{198}

= \frac{1}{66}  (Answer)                                                          

7 0
4 years ago
F(x)5x + 4<br> Find f(6)
saul85 [17]

\sf{Hello!}

f(x) = 5x + 4

f(6) =  ----

f(6) = 5(6) + 4

f(6) = 30 + 4

f(6) = 34

Have a nice day!

6 0
3 years ago
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A rectangular prism is 4 m long 5 m wide and has a height of 6 m what is its surface area
asambeis [7]

<em><u>hope it helps you see the attachment for further information..... </u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em><em><u>✨</u></em>

3 0
3 years ago
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