3 years ago

S^2-42s+180=0 solve it

Mathematics

1 answer:

Verdich [7]3 years ago

7 0

Answer:

s2−42s+180=0

Step 1: Use quadratic formula with a=1, b=-42, c=180.

−b±√b2−4ac

−(−42)±√(−42)2−4(1)(180)

2(1)

42±√1044

s=21+3√29 or s=21−3√29

Answer:

s=21+3√29 or s=21−3√29

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S^2-42s+180=0 solve it​

S^2-42s+180=0 solve it