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3 years ago

Can u help me with the orginal slope and perpendicular slope. And tell me where to plot the points

Mathematics

1 answer:

Darya [45]3 years ago

8 0

Answer: The original slope is 1.

To plot the line with perpendicular slope, try coordinates (0,0) and (6,-6)

The perpendicular slope is negative 1.

Step-by-step explanation:

The rise is 6, the run is 6.

6/6 = 1

The slope of the perpendicular line is the reciprocal of the original slope. and has the opposite sign-- switch neg to pos or pos to neg.

If the original slope is 2, the perpendicular will be -1/2

Reciprocal means the number (usually a fraction) that you multiply by the original number to get 1 as the product. 3×1/3 = 1 . 1/5×5 = 1

Since 1 is already 1, 1 is the reciprocal of itself!

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The 99% confidence interval for the population proportion is given by

$sample \ proportion \pm 2.575\times standard \ error$

Given that 52% = 0.52 is the standard proportion and the standard error is 2.4% = 0.024.

Therefore, the <span>99% confidence interval for the fraction of u.s. adult twitter users who get some news on twitter is given by

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The interpretation of the confidence interval</span> is as follows: "We are 99% confident that the fraction of U.S. adult twiter users who get some news on twitter is between 45.82% and 58.18%.

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3 years ago

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Check all of the points that are solutions!

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3 years ago

Determine whether each table or graph represents a proportional

Snezhnost [94]

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(2x^3-3x^2-18x-8)/(x-4) Divide by long division

marin [14]

Answer:

$(2\, x^{3} - 3\, x^{2} - 18\, x - 8) / (x - 4) = (2\, x^{2} + 5\, x + 2)$ .

Step-by-step explanation:

The leading term of a one-variable polynomial refers to the term with the highest power of the variable. For example, in the polynomial $(2\, x^{3} - 3\, x^{2} - 18\, x - 8)$ , $x$ is the variable, and $2\, x^{3}$ is the leading term. The power of the leading term $2\, x^{3}\!$ is $3$ .

The numerator is $(2\, x^{3} - 3\, x^{2} - 18\, x - 8)$ while the denominator is $(x - 4)$ .

Leading term of the numerator: $2\, x^{3}$ .
Leading term of the denominator: $x$ .

Divide the leading term of the numerator by the leading term of the denominator to find the next term of the quotient. In this case, $(2\, x^{3}) / (x) = 2\, x^{2}$ .

Multiply the denominator by the quotient that was just found. In this case, $2\, x^{2}\, (x - 4) = 2\, x^{3} - 8\, x^{2}$ . Subtract this product from the current numerator to find the next numerator:

$\begin{aligned} & (2\, x^{3} - 3\, x^{2} - 18\, x - 8) - (2\, x^{3} - 8\, x^{2}) \\ =\; & 2\, x^{3} - 3\, x^{2} - 18\, x - 8 - 2\, x^{3} + 8\, x^{2}\\=\; & 5\, x^{2} - 18\, x - 8\end{aligned}$ .

Thus, the next numerator would be $(5\, x^{2} - 18\, x - 8)$ . The denominator stays

the same.

Repeat the steps above until the power of the numerator is less than that of the denominator.

The numerator is $(5\, x^{2} - 18\, x - 8)$ while the denominator is still $(x - 4)$ .

Leading term of the numerator: $5\, x^{2}$ .
Leading term of the denominator: $x$ .

Next term of the quotient: $(5\, x^{2}) / (x) = 5\, x$ . Add that term to the quotient. The quotient is now $(2\, x^{2} + 5\, x)$ .

The next numerator should be:

$\begin{aligned} & (5\, x^{2} - 18\, x - 8) - 5\, x \, (x - 4) \\ =\; & (5\, x^{2} - 18\, x - 8) - (5\, x^{2} - 20) \\ =\; & 2\, x - 8\end{aligned}$ .

The numerator is now $(2\, x - 8)$ while the denominator continues to be the same.

Leading term of the numerator: $2\, x$ .
Leading term of the denominator: $x$ .

Next term of the quotient: $(2\, x) / (x) = 2$ . Add that term to the quotient to get $(2\, x^{2} + 5\, x + 2)$ .

The next numerator should be:

$\begin{aligned} & (2\, x - 8) - 2\, (x - 4) \\ =\; & (2\, x - 8) - (2\, x - 8) \\ =\; & 0 \end{aligned}$ .

The numerator is now a constant. The power of $x$ is the current numerator would be $0$ . The power of $x\!$ in the denominator continues to be $1$ . Thus, the power of the numerator is now less than that of the denominator.

The quotient is now the required quotient, with the "numerator" being the remainder of the division. That is:

$(2\, x^{3} - 3\, x^{2} - 18\, x - 8) = (2\, x^{2} + 5\, x + 2)\, (x - 4) + 0$ .

$(2\, x^{3} - 3\, x^{2} - 18\, x - 8) = (2\, x^{2} + 5\, x + 2)\, (x - 4)$ .

Equivalently:

$(2\, x^{3} - 3\, x^{2} - 18\, x - 8) / (x - 4) = (2\, x^{2} + 5\, x + 2)$ .

7 0

3 years ago