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2 years ago

Please find x and a

Mathematics

1 answer:

aev [14]2 years ago

8 0

Answer:

x = 36

a = 25

Step-by-step Explanation

By Pythagoras Theorem:

$x = \sqrt{ {39}^{2} - {15}^{2} } \\ \\ x = \sqrt{1,521 - 225} \\ \\ x = \sqrt{1,296} \\ \\ x = 36 \\ \\ a = \sqrt{ {20}^{2} + {15}^{2} } \\ \\ a = \sqrt{400 + 225} \\ \\ a = 25 \sqrt{625} \\ \\ a = 25$

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ladder 5m tall when set against a wall of house just reach the window at a height 3m how far is the lower end of ladder from the

KATRIN_1 [288]

Answer:

Step-by-step explanation:

A simple matter of using Pythagoras. The hypotenuse is the ladder, and one of the legs is the wall, and we have to figure out the value of the other leg.

The Pythagorean formuda is (hypotenuse = a): a² + b² = c² (b and c are the other sides)

applying the values: a = 5 and b or c is 3 (I'll put b = 3)

5² = 3² + c²

25 = 9 + c²

25 - 9 = c²

16 = c²

√16 = c

4 = c

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2 years ago

The graph of g is a vertical stretch by a factor of 4 and a reflection in the x-axis, followed by a translation 2 units up of th

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3 years ago

PLEASE HELP ASAP

maria [59]

Answer:

First option: $3x^2-5x=-8$

Second option: $2x^2=6x-5$

Fourth option: $-x^2-10x=34$

Step-by-step explanation:

Rewrite each equation in the form $ax^2+bx+c=0$ and then use the Discriminant formula for each equation. This is:

$D=b^2-4ac$

1) For $3x^2-5x=-8$ :

$3x^2-5x+8=0$

Then:

$D=(-5)^2-4(3)(8)=-71$

Since $D$ this equation has no real solutions, but has two complex solutions.

2) For $2x^2=6x-5$ :

$2x^2-6x+5=0$

Then:

$D=(-6)^2-4(2)(5)=-4$

Since $D$ this equation has no real solutions, but has two complex solutions.

3) For $12x=9x^2+4$ :

$9x^2-12x+4=0$

Then:

$D=(-12)^2-4(9)(4)=0$

Since $D=0$ this equation has one real solution.

4) For $-x^2-10x=34$ :

$-x^2-10x-34=0$

Then:

$D=(-10)^2-4(-1)(-34)=-36$

Since $D$ , this equation has no real solutions, but has two complex solutions.

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3 years ago

Select the correct answer. What is the surface area of the victory podium shown here? Include all surfaces of the podium, includ

Leya [2.2K]

Answer:

Option C is correct.

Step-by-step explanation:

Given the dimension of the surfaces i.e length, width and height of podium. we have to calculate the surface area of the victory podium.

As Surface area of cuboid is 2(LW+WH+HL)

In the given figure, the upper cuboid has dimension

L=2.5 ft. , W=1.5 ft, H=1.5 ft

$\text{Surface area=}2(2.5(1.5)+1.5(1.5)+1.5(2.5))=19.5ft^2$

$\text{Area of bottom face of upper cuboid=}L\timesW=2.5\times1.5=3.75ft^2$

The upper face is occuring twice therefore it must be subtracted to find the area

Dimensions of lower podium are

L=7.5 ft. , W=1.5 ft, H=1.5 ft

$\text{Surface area=}2(7.5(1.5)+1.5(1.5)+1.5(7.5))=49.5ft^2$

Now, Surface area of podium included bottom is

19.5+49.5-3.75=65.25 square feet.

Hence, option C is correct.

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3 years ago

10x+8=3(x-2) 10x+8=3x-6

d1i1m1o1n [39]

Answer:

x = -2

Step-by-step explanation:

10x+8=3x-6

subtract 10x-3x

7x+8= -6

subtract -6-8

7x=-14

divide 7 into -14

x = -2

Hope this helps!

4 0

2 years ago

Please find x and a​

Please find x and a