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Triss [41]
3 years ago
8

SkinnieQueen2019 got a 23/25 on her math test. What percent did she get?

Mathematics
2 answers:
True [87]3 years ago
6 0
92% 23 divided by 25 is 0.92
Westkost [7]3 years ago
3 0

Answer: 92%

Step-by-step explanation:

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Please help with these quick
drek231 [11]
To determine whether 10a-10c are true or false, you first need to know how to find the volume of the shoebox and the volume of the crate.

The equation for volume is l × w × h where l is the length, w is the width, and h is the height.

So, the volume of the shoebox is

V = l × w × h
V = 12 × 6 × 4
V = 288 cubic inches.

To find the volume of the crate, we simply multiply the volume of one shoebox by 20, as the crate holds 20 shoeboxes.

228 × 20 = 4560 cubic inches.

10a. Each shoebox has a volume of 22 cubic inches. <span>False. The volume is 228 cubic inches.

</span>10b. Each crate has a volume of about 440 cubic inches. <span>False. The volume of each crate is 4560 cubic inches.</span><span>

</span>10c. If the crate could hold 27 shoeboxes, the volume of the crate would be about 7,776 cubic inches.

For this one, let's do some more math. Since we figured out the volume of a crate holding 20 shoeboxes is 4560 cubic inches, let's do the same thing to find the volume of a crate holding 27 shoeboxes.

228 × 27 = 6156 cubic inches.

<span>False. The volume of a crate holding 27 shoeboxes would be 6156 cubic inches.

</span>11 part A:

Each term above describes the term below, but the term below doesn't necessarily describe the term above.

The choice of terms is : <span>trapezoid</span>, <span>triangle</span>, <span>rhombus</span>, <span>parallelogram</span>

Before we do anything else, let's define our terms, as well as the ones used in the diagram.

Trapezoid - A four sided shape with a pair opposite parallel sides.<span>
Triangle - </span>A shape with three sides.<span>
Rhombus - </span>A shape with four equal straight sides<span>.
Parallelogram - </span>A quadrilateral with two sets of parallel sides.<span>
Quadrilateral - </span>A four-sided shape with four angles.<span>
Square - </span>A four-sided shape with all four sides the same length, and all four angles are the same size.

The first term is quadrilateral. From this, we can determine that the term <span>triangle</span> won't be used at all, as it's a three-sided figure, whereas a <span>quadrilateral</span> is a four-sided figure. This leaves <span>trapezoid, rhombus, </span>and <span>parallelogram </span>as our terms.

A <span>trapezoid </span>is a <span>quadrilateral</span>, because it has four sides, but it can't be a <span>rhombus </span>or <span>parallelogram</span>, so it goes in the first open box.

A parallelogram is a trapezoid, because it has a pair of opposite parallel sides, but it can't be a rhombus, because it doesn't necessarily have all equal sides, so it goes in the second open box.

A rhombus is a parallelogram, because it has two sets of parallel sides, and goes in the third open box.

So, from top box to bottom box, the order the term go is
Quadrilateral
Trapezoid
Parallelogram
Rhombus
Square

3 0
4 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
3 years ago
The Florida Everglades welcomes about
Bingel [31]

Answer:

14,000 visitors weekly

Step-by-step explanation:
Break the Equation Down.

10^3 = 10 x 10 x 10

10x10x10=1000 V

Put the 1000 within the problem.

2 x 1000

Solve

2 x 1000 = 2000 Visitors

7 days are within a week so multiply the daily visitors (2000) by 7

2000 x 7 = 14,000


Answer: 14,000 visitors weekly


Hope you like this way of solving! Let me know if have any questions!

3 0
2 years ago
Please help Me 41 points
nexus9112 [7]

Answer: u already have the answer so thank u for the answer and the 21. Points

Step-by-step explanation:

3 0
3 years ago
Someone plz help me. There are 2 answer choices
givi [52]

ik the first answer choice is false

3 0
3 years ago
Read 2 more answers
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