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creativ13 [48]
3 years ago
5

Answer and maybe an explanation.Thanks in advance.

Mathematics
1 answer:
qaws [65]3 years ago
3 0
Inverses

solve for x
replace x with f inverse
replace y with x



so
first minus 2 both sides
y-2=√(2x-3)
square both sides
y^2-4y+4=2x-3
add 3 to both sides
y^2-4y+7=2x
divide both sides y 2
(y^2-4y+7)/2=x

x turns to f inverse and y turns to x


f(x)⁻¹=\frac{x^{2}-4x+7}{2}


looks like they didn't want to expand the binomial

y=\frac{(x-2)^{2}}+3}{2}
answer si A
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Can someone help me with number 8 please? Thank you.
Naddik [55]
Answer: -4 \le x \le 5
Note: to write the domain in interval notation, you'd write [-4,5]
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Explanation:

The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.

So that's how I got -4 \le x \le 5 (x is between -4 and 5; inclusive of both endpoints)

Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"

Writing \left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\} is the set-builder notation way of expressing the domain. The x\in\mathbb{R} portion means "x is a real number"

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