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s344n2d4d5 [400]
3 years ago
12

RS= 4y+2, ST = 3y+8, and RT = 38 what is the value of y

Mathematics
1 answer:
emmainna [20.7K]3 years ago
7 0

Answer:

y = 4

Step-by-step explanation:

Given that,

RS= 4y+2, ST = 3y+8, and RT = 38

We need to find the value of y.

As,

RT = RS+ST

Put all the values,

38 = 4y+2+3y+8

38-2-8 = 4y+3y

28 = 7y

y = 4

So, the value of y is equal to 4.

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Which expression is equivalent to 6p + 6p?<br><br> A. 12p<br> B. 36p<br> C. 12 + 2p<br> D. p6
sveticcg [70]
Hello!

6p + 6p = 12p

The answer is A)12p

Hope this helps!
6 0
3 years ago
Rewrite the equation by completing the square. 4 x^{2} +20x +25 =0
Ede4ka [16]

Answer:

(x+5/2)^2 = 0

Step-by-step explanation:

4 x^{2} +20x +25 =0

Divide by 4

4/4 x^{2} +20/4x +25/4 =0

x^2 +5x +25/4 =0

Subtract 25/4 from each side

x^2 +5x +25/4 -25/4 =-25/4

x^2 +5x  =-25/4

Take the coefficent of x

5

Divide by 2

5/2

Square it

25/4

Add it to each side

x^2 +5x +25/4 =-25/4+25/4

(x+5/2)^2 = 0

Take the square root of each side

x+5/2 = 0

x = -5/2

8 0
2 years ago
Read 2 more answers
QUICK PLEASE!!<br><br> -5.6 = h/5 + 12.2<br> show steps!
BaLLatris [955]

Answer: h = 89

Step-by-step explanation:  Hope correct :)

3 0
2 years ago
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Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12
irina [24]

Answer:

Part 1) The perimeter is  P=6\sqrt{6}\ cm

Part 2) The diagonal is d=\sqrt{30}\ cm

Step-by-step explanation:

<u><em>The question in English is</em></u>

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

A=bh

A=12\ cm^2

so

bh=12 ----> equation A

The base is twice the height

so

b=2h ----> equation B

substitute equation B in equation A

(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm

Find the value of b

b=2\sqrt{6}\ cm

step 2

Find the perimeter of rectangle

The perimeter is given by

P=2(b+h)

substitute

P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

d^2=b^2+h^2

substitute

d^2=(2\sqrt{6})^2+(\sqrt{6})^2

d^2=30

d=\sqrt{30}\ cm

3 0
3 years ago
Which expression is equivalent to the given expression?
I am Lyosha [343]

Answer:

C. - 4x^2 + 5x - 4

Step-by-step explanation:

just expand the equation and you'll get C

6 0
3 years ago
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