Solve for xxx. 12x+7 4012x+7 4012, x, plus, 7, is less than, minus, 11, start color #ed5fa6, start text, space, O, R, space, end
gregori [183]
Answer:
<h2>
x < -3/2 and x>48/5</h2>
Step-by-step explanation:
Given the inequality function 12x+7< -11 and 5x-8>40, we are to solve for the value of x. To solve for x, the following steps must be followed.
For the inequality 12x+7< -11
Step 1: Subtract 7 from both sides of the inequality
12x+7-7< -11-7
12x < -18
Step 2: Divide both sides of the inequality by 12
12x/12 < -18/12
x < -3/2 .............. 1
For the inequality 5x-8> 40;
Step 1: Add 8 to both sides of the inequality
5x-8+8 > 40+8
5x > 48
Step 2: Divide both sides of the inequality by 5
5x/5 > 48/5
x>48/5....... 2
Combining equation 1 and 2, we will have;
x < -3/2 and x>48/5
If x>48/5 then 48/5<x
Combining 48/5<x with x < -3/2 will give 48/5<x<-3/2
complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
Answer:$5 dollars
Step-by-step explanation:
