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steposvetlana [31]

3 years ago

10

What is 72% as a fraction and decimal

1 answer:

RoseWind [281]3 years ago

6 0

72% as a decimal is 0.72.
<span>72% as a fraction is 72/100 = 18/25

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Solve the following system of equations graphically, Select the graph that shows the correct solution of the systern.

Reptile [31]

Answer:

a

Step-by-step explanation:

8 0

2 years ago

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The number of fish (f) in a fish tank increases when the number of algae blooms (a) decreases. Write the correct equation for th

Artyom0805 [142]

Answer:

f = -2/5a +14
12.4 ≈ 12 fish for 4 algae blooms

Step-by-step explanation:

The 2-point form of the equation for a line is useful when you are given two points to work with:

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

The independent variable (x) is apparently "algae blooms" and is to be represented by "a". The dependent variable (y) is "number of fish" and is to be represented by "f". So, we have ...

f = (4 -10)/(25 -10)(a -10) +10

f = -6/15(a -10) +10

f = -2/5a +14 . . . an equation for the scenario

Four a=4, the fish population is predicted to be ...

f = -2/5(4) +14 = 12.4

There will be about 12 fish when there are 4 algae blooms.

6 0

2 years ago

Let a1, a2, a3, ... be a sequence of positive integers in arithmetic progression with common difference

Bezzdna [24]

Since $a_1,a_2,a_3,\cdots$ are in arithmetic progression,

$a_2 = a_1 + 2$

$a_3 = a_2 + 2 = a_1 + 2\cdot2$

$a_4 = a_3+2 = a_1+3\cdot2$

$\cdots \implies a_n = a_1 + 2(n-1)$

and since $b_1,b_2,b_3,\cdots$ are in geometric progression,

$b_2 = 2b_1$

$b_3=2b_2 = 2^2 b_1$

$b_4=2b_3=2^3b_1$

$\cdots\implies b_n=2^{n-1}b_1$

Recall that

$\displaystyle \sum_{k=1}^n 1 = \underbrace{1+1+1+\cdots+1}_{n\,\rm times} = n$

$\displaystyle \sum_{k=1}^n k = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2$

It follows that

$a_1 + a_2 + \cdots + a_n = \displaystyle \sum_{k=1}^n (a_1 + 2(k-1)) \\\\ ~~~~~~~~ = a_1 \sum_{k=1}^n 1 + 2 \sum_{k=1}^n (k-1) \\\\ ~~~~~~~~ = a_1 n + n(n-1)$

so the left side is

$2(a_1+a_2+\cdots+a_n) = 2c n + 2n(n-1) = 2n^2 + 2(c-1)n$

Also recall that

$\displaystyle \sum_{k=1}^n ar^{k-1} = \frac{a(1-r^n)}{1-r}$

so that the right side is

$b_1 + b_2 + \cdots + b_n = \displaystyle \sum_{k=1}^n 2^{k-1}b_1 = c(2^n-1)$

Solve for $c$ .

$2n^2 + 2(c-1)n = c(2^n-1) \implies c = \dfrac{2n^2 - 2n}{2^n - 2n - 1} = \dfrac{2n(n-1)}{2^n - 2n - 1}$

Now, the numerator increases more slowly than the denominator, since

$\dfrac{d}{dn}(2n(n-1)) = 4n - 2$

$\dfrac{d}{dn} (2^n-2n-1) = \ln(2)\cdot2^n - 2$

and for $n\ge5$ ,

$2^n > \dfrac4{\ln(2)} n \implies \ln(2)\cdot2^n - 2 > 4n - 2$

This means we only need to check if the claim is true for any $n\in\{1,2,3,4\}$ .

$n=1$ doesn't work, since that makes $c=0$ .

If $n=2$ , then

$c = \dfrac{4}{2^2 - 4 - 1} = \dfrac4{-1} = -4 < 0$

If $n=3$ , then

$c = \dfrac{12}{2^3 - 6 - 1} = 12$

If $n=4$ , then

$c = \dfrac{24}{2^4 - 8 - 1} = \dfrac{24}7 \not\in\Bbb N$

There is only one value for which the claim is true, $c=12$ .

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1 year ago

NemiM [27]

Answer:

D. 2 3 • 3 2 • 5

Step-by-step explanation:

ig I need at least 20 characters to submit my answer. :)

8 0

2 years ago

In ΔABC, ∠A is a right angle. What is the value of y?

Bogdan [553]

Y = 7sin(30) = 3.5
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7 0

2 years ago

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