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Misha Larkins [42]
3 years ago
14

Yo plz help me with this!! worth 20 points

Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

We need the answer choices!!!

Step-by-step explanation:

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Marla bought one necklace and two bracelets for $67.50. Use the following information to determine the amount she paid for each
alexdok [17]
Ooh, scary math

n+2b=67.5
n=27
27+2b=67.5
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3 years ago
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Given that the product of 22 integers is equal to 1, prove that their sum is not equal to 0.
Kay [80]

1. If the product of these integers is to be 1, then all of them must be either 1 or -1.

2. Since the product is positive (+1), it must be that there are an *even* number of negative ones (-1), if any.

3. If the sum were 0 it would mean that the number of +1's must equal the number of -1's. So that means there would have to be exactly 22/2=11 of each.

4. But if there were 11 of each, that means the number of -1's would be *odd* and there's no way the product could be +1 (as stated in 2 above).

Hence, the sum is never 0, if the product of 22 integers is equal +1.

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3 years ago
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Simplified it should be 4x^10y^8
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Solve the formula for the variable h f=12gh
Contact [7]
To solve for variable h flip the equation. You get: 12gh=f. After, divide both sides by 12 to get your answer: h=f/12g
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