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pishuonlain [190]

2 years ago

9

What is the solution to the system of equations below?

1 answer:

katen-ka-za [31]2 years ago

7 0

$4x - y = - 5 \\ - 2x + y = 3$

Solve the second equation for y

$4x - y = - 5 \\ y = 3 + 2x$

Substitute the given value of y into the first equation

$4x - (3 + 2x) = - 5$

Solve the equation for x

$x = - 1$

Substitute the given value of x into the second equation

$y = 3 + 2( - 1)$

Solve the equation for y

$y = 1$

The possible solution of the system is the ordered pair (x,y)

$(x,y) = ( - 1, 1)$

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Solve the equation for the indicated variable.<br>1. y= 3/8 (x+4) for x

madam [21]

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6 0

3 years ago

Read 2 more answers

Plz help me with this math and also explain

jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

SI = $250
Rate (R) = 12 $\sf \dfrac{1}{2}$ %
Time (t) = 4 years

$\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\$

$\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\$

$\longrightarrow \tt { 250 \times 100 = P \times 50} \\$

$\longrightarrow \tt { 25000 = P \times 50} \\$

$\longrightarrow \tt { \dfrac{25000}{50} = P } \\$

$\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\$

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

2/7 of the balls are red.
3/5 of the balls are blue.
Rest are yellow.
Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

$\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\$

$\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\$

$\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\$

$\longrightarrow \tt{ 31x + 1260= 35x} \\$

$\longrightarrow \tt{ 1260= 35x-31x} \\$

$\longrightarrow \tt{ 1260= 4x} \\$

$\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\$

$\longrightarrow \underline{\boxed{ \tt { 315 = x }}} \\$

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

$\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\$

$\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\$

$\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\$

$\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\$

8 0

3 years ago