Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:

The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.
X = 82:


Z = 1
Z = 1 has a p-value of 0.84.
X = 72:


Z = 0
Z = 0 has a p-value of 0.5.
0.84 - 0.5 = 0.34.
Out of 200 students, the number is given by:
0.34 x 200 = 68 students with scores between 72 and 82.
More can be learned about the normal distribution at brainly.com/question/24663213
#SPJ1
Step-by-step explanation:
Confidence interval = mean ± margin of error
CI = μ ± ME
The mean is μ = 8.7.
Margin of error = critical value × standard error
ME = CV × SE
At 95% confidence and 9 degrees of freedom, CV = 2.262.
SE = s / √n
SE = 3.3 / √10
SE = 1.04
The margin of error is:
ME = 2.262 × 1.04
ME = 2.36
CI = 8.7 ± 2.36
CI = (6.34, 11.06)
Answer:
maximum height of the arrow will be 408 m
Step-by-step explanation:
We have given the function of height as 
We know that first derivative of height will be velocity
So first derivative of height


We know that at maximum height velocity will be zero

t = 5 sec
Sp arrow will be at maximum height at t = 5 sec
So height at t = 5 sec will be

So maximum height of the arrow will be 408 m
since we know those two triangles are similar then we can use proportions.
![\cfrac{AE}{AB}=\cfrac{AD}{AC}\implies \cfrac{14-8}{2x}=\cfrac{14}{2x+4}\implies \cfrac{6}{2x}=\cfrac{14}{2x+4}\implies \cfrac{3}{x}=\cfrac{14}{2x+4} \\\\\\ 6x+12=14x\implies 12=8x\implies \cfrac{12}{8}=x\implies \cfrac{3}{2}=x \\\\[-0.35em] ~\dotfill\\\\ AB=2x+4\implies AB=2\left( \frac{3}{2} \right)+4\implies AB=3+4\implies AB=7](https://tex.z-dn.net/?f=%5Ccfrac%7BAE%7D%7BAB%7D%3D%5Ccfrac%7BAD%7D%7BAC%7D%5Cimplies%20%5Ccfrac%7B14-8%7D%7B2x%7D%3D%5Ccfrac%7B14%7D%7B2x%2B4%7D%5Cimplies%20%5Ccfrac%7B6%7D%7B2x%7D%3D%5Ccfrac%7B14%7D%7B2x%2B4%7D%5Cimplies%20%5Ccfrac%7B3%7D%7Bx%7D%3D%5Ccfrac%7B14%7D%7B2x%2B4%7D%20%5C%5C%5C%5C%5C%5C%206x%2B12%3D14x%5Cimplies%2012%3D8x%5Cimplies%20%5Ccfrac%7B12%7D%7B8%7D%3Dx%5Cimplies%20%5Ccfrac%7B3%7D%7B2%7D%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20AB%3D2x%2B4%5Cimplies%20AB%3D2%5Cleft%28%20%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%2B4%5Cimplies%20AB%3D3%2B4%5Cimplies%20AB%3D7)