What property is illustrated here: (−1) = (−1)(1) = −1 ?

the city park department is planning to enclose a play aea. one side of the area will be against an existing building, so no fen

SVEN [57.7K]

Answer:

length = 200 m

width = 400 m

Step-by-step explanation:

Let the length of the plaing area is L and the width of the playing area is W.

Length of fencing around three sides = 2 L + W = 800

W = 800 - 2L ..... (1)

Let A is the area of playing area

A = L x W

A = L (800 - 2L)

A = 800 L - 2L²

Differentiate with respect to L.

dA/dL = 800 - 4 L

It is equal to zero for maxima and minima

800 - 4 L = 0

L = 200 m

W = 800 - 2 x 200 = 400 m

So, the area is maximum if the length is 200 m and the width is 400 m.

8 0

2 years ago

Read 2 more answers

Match each set of points with the slope of the line formed by the ordered pairs.

Maksim231197 [3]

Answer:

(0,7) and (2,4) go to slope =-3/2

(1,-3) and (-1,-3) go to zero slope

(0,0) and (2,1) go to slope =1/2

(0,-1) and (2,-5) go to slope =-2

and (-1,3) and (-1,-3) go to no slope

Step-by-step explanation:

i did the edge 2020 thing

3 0

2 years ago

Read 2 more answers

I WILL MARK BRAINLIEST!!!! An underground mine elevator descends 12% of the total depth every minute. The total depth of the ele

Dahasolnce [82]

Answer:

after 1 Min it's -9

after 2 mins it's -1.08

Step-by-step explanation:

12% X 75 = 9

12% X 9 = 1.08

3 0

2 years ago

Read 2 more answers

A shopkeeper allows 10% discount on the marked price of a bicycle. If a costomer pays Rs 4068 with 13% VAT find the marked price

Over [174]

$\large{ \tt{❁ \: S \: O \: L \: U \: T \: I \: O \: N \: ❁}}$

We're provided - Discount % = 10 % , Cost with VAT [ SP with VAT ] = Rs 4068 & VAT % = 13%. We're asked to find out the marked price of the bicycle. Let's start :

$\large{ \tt{❇ \: FIND \: SP \: WITHOUT \: VAT \: / \: SP\: ❇}}$

$\large{ \tt{❃ \: SP \: with \: VAT= SP + VAT\% \: of \: SP}}$

$\large{ \tt{⇢ \: 4068 = SP + 13\% \: of \: SP}}$

$\large{ \tt{⇢ \: 4068 = SP + \frac{13}{100} \: sp}}$

$\large{ \tt{⇢ \: 4068 = \frac{100 \: \: SP + 13 \: SP}{100} }}$

$\large{ \tt{⇢ \: 4068 = \frac{113 \: SP}{100} }}$

$\large{ \tt{⇢ \: 113 \: SP = 406800}}$

$\large{ \tt{⇢ \: SP = \frac{406800}{113} }}$

$\large{ \tt{⇢ \: SP = 3600}}$

Hence , SP = Rs 3600

$\large{ \tt{✽ \: NOW , \: FIND \: THE \: MP \:✽ }}$

Let Marked Price [ MP ] be x.

$\large {\tt{❃ \: SP = MP - dis\% \: of \: MP}}$

$\large{ \tt{⇾ \: 3600 = x - 10\% \: of \: x}}$

$\large{ \tt{⇾ \: 3600 = x - \frac{10}{100} } \: x}$

$\large{ \tt{⇾ \: 3600 = \frac{100x - 10x}{100} }}$

$\large{ \tt{⇾ \: 3600 = \frac{90x}{100} }}$

$\large{ \tt{⇾ \: 90x = 360000}}$

$\large{ \tt{⇾ \: x = \frac{360000}{90} }}$

$\large{ \tt{⇾ \: x = Rs \: 4000}}$

$\large{ \boxed{ \boxed{ \tt{☂ \: OUR \: FINAL \: ANSWER : \boxed {\tt {\: Rs \: 4000}}}}}}$

Hope I helped! Let me know if you have any questions regarding my answer and don't hesitate to reach out to me if you need any assistance! :)

6 0

2 years ago

What is the image of (-5, 6) after a reflection over the line y = -2

prohojiy [21]

Answer:

I'm pretty sure it would be (5,6)

Step-by-step explanation:

Reflecting a point over the Y-axis would change the x-coordinate, but not the y-coordinate

6 0

2 years ago