Answer:
167.27 mg.
Step-by-step explanation:
We have been given that the half-life of Radium-226 is 1590 years and a sample contains 400 mg.
We will use half life formula to solve our given problem.
, where N(t)= Final amount after t years,
= Original amount, t/2= half life in years.
Now let us substitute our given values in half-life formula.


Therefore, the remaining amount of Radium-226 after 2000 years will be 167.27 mg.
Answer:
54.8 Nm
Step-by-step explanation:
Torque is the cross product of the radius vector and force vector:
τ = r × F
Another way to write it is the product of the radius and force magnitudes times the sine of the angle between the vectors.
τ = rF sin θ
Here, r = 0.366 meters and F = 155 Newtons. F is in the +y direction, and r is 15° below the +x axis, so the angle between the vectors is 90° − 15° = 75°.
τ = (0.366 m) (155 N) (sin 75°)
τ = 54.8 Nm
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<span>9 divided by 3/2
= 9 (2/3)
= 6
--------------</span>
Answer:
132
Step-by-step explanation:
Straight lines add up to 180
180-48=132