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3 years ago

Hello does anyone know how to figure this out? - 3(4 + x) = x + 6

Mathematics

2 answers:

exis [7]3 years ago

6 0

Answer:

-4.5

Step-by-step explanation:

-12-3x=x+6

-4x=18

x=-4.5

galben [10]3 years ago

4 0

Answer:

-4.5=x

Step-by-step explanation:

First you would distribute the -3 to the 4 and x inside the parentheses

It would be -3 x 4= -12

Then -3 x X= -3x

So your equation would now be -12+ -3x = x + 6

Now you add 3x to the -3x to cancel it out and then add it to the x

So your equation now looks like -12=4x +6

Then you subtract 6 from the 6 to cancel it out and add it to the -12

Now your equation looks like -18=4x

Then you divide 4 from the 4x to cancel it out and then divide 4 from the -18

Finally you have -4.5=x

I'm unsure if this is correct but hopefully this helps :)

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Jaron walked 15 blocks north and then 3 blocks west to school. Marisol walked 3 blocks east and then 15 blocks south to school.

Svet_ta [14]

Answer:

sqrt(15² + 3²) = sqrt(15² + 3²)

Step-by-step explanation:

Using Pythagoras:

15 blocks North = 15 blocks south (direction opposite to each other)

3 blocks west = 3 blocks east (directions opposite to each other)

Hence distance traveled (d) :

JARON

D = sqrt(15² + 3²)

MARISOL:

D = sqrt(15² + 3²)

Hence ;

sqrt(15² + 3²) = sqrt(15² + 3²)

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3 years ago

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lions [1.4K]

Answer:

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6 0

3 years ago

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4 years ago

Solve (16×^3-3×^2+43×-5)÷(×^2-2)

Oksana_A [137]

Answer:

3872/(x^2 - 2)

Step-by-step explanation:

Simplify the following:

(16^3 - 3^2 - 5×43)/(x^2 - 2)

3^2 = 9:

(16^3 - 9 - 5×43)/(x^2 - 2)

16^3 = 16×16^2:

(16×16^2 - 9 - 5×43)/(x^2 - 2)

| 1 | 6

× | 1 | 6

| 9 | 6

1 | 6 | 0

2 | 5 | 6:

(16×256 - 9 - 5×43)/(x^2 - 2)

16×256 = 4096:

(4096 - 9 - 5×43)/(x^2 - 2)

43 (-5) = -215:

(4096 - 9 + -215)/(x^2 - 2)

4096 - 9 - 215 = 3872:

Answer: 3872/(x^2 - 2)

7 0

3 years ago

A random sample of size n1= 25, taken from a normal population with a standard deviation σ1= 5, has a mean X1= 80. A second rand

sesenic [268]

Answer:

The 94% confidence interval would be given by $2.898 \leq \mu_1 -\mu_2 \leq 7.102$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =80$ represent the sample mean 1

$\bar X_2 =75$ represent the sample mean 2

n1=25 represent the sample 1 size

n2=36 represent the sample 2 size

$\sigma_1 =5$ sample standard deviation for sample 1

$\sigma_2 =3$ sample standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =80-75=5$

Since the Confidence is 0.94 or 94%, the value of $\alpha=0.06$ and $\alpha/2 =0.03$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.03,0,1)".And we see that $z_{\alpha/2}=1.88$