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3 years ago

I need help with this

Mathematics

1 answer:

Inessa [10]3 years ago

8 0

Answer:

I WAS BORN TO FLEX DIMONDS ON MY NECK I LIKE MORNING CHECKS I LIKE MORING S**

Step-by-step explanation:

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Greenwood Lake is pictured below on a grid where each square has sides that are 1 mile long.

alisha [4.7K]

6 square units.
1 sq units would be 1 mile, so 4 units are 4 miles. A little bit more than 4 is 6.

8 0

3 years ago

Parallel / Perpendicular Practice

deff fn [24]

The slope and intercept form is the form of the straight line equation that includes the value of the slope of the line

Neither
║
Neither
⊥
║
Neither
Neither
Neither

Reason:

The slope and intercept form is the form y = m·x + c

Where;

m = The slope

Two equations are parallel if their slopes are equal

Two equations are perpendicular if the relationship between their slopes, m₁, and m₂ are; $m_1 = -\dfrac{1}{m_2}$

1. The given equations are in the slope and intercept form

$\ y = 3 \cdot x + 1$

The slope, m₁ = 3

$y = \dfrac{1}{3} \cdot x + 1$

The slope, m₂ = $\dfrac{1}{3}$

Therefore, the equations are neither parallel or perpendicular

Neither

2. y = 5·x - 3

10·x - 2·y = 7

The second equation can be rewritten in the slope and intercept form as follows;

$y = 5 \cdot x -\dfrac{7}{2}$

Therefore, the two equations are parallel

3. The given equations are;

-2·x - 4·y = -8

-2·x + 4·y = -8

The given equations in slope and intercept form are;

$y = 2 -\dfrac{1}{2} \cdot x$

Slope, m₁ = $-\dfrac{1}{2}$

$y = \dfrac{1}{2} \cdot x - 2$

Slope, m₂ = $\dfrac{1}{2}$

The slopes

Therefore, m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

The lines are Neither parallel nor perpendicular

Neither

4. The given equations are;

2·y - x = 2

$y = \dfrac{1}{2} \cdot x +1$

m₁ = $\dfrac{1}{2}$

y = -2·x + 4

m₂ = -2

Therefore;

$m_1 \neq -\dfrac{1}{m_2}$

Therefore, the lines are perpendicular

5. The given equations are;

4·y = 3·x + 12

-3·x + 4·y = 2

Which gives;

First equation, $y = \dfrac{3}{4} \cdot x + 3$

Second equation, $y = \dfrac{3}{4} \cdot x + \dfrac{1}{2}$

Therefore, m₁ = m₂, the lines are parallel

6. The given equations are;

8·x - 4·y = 16

Which gives; y = 2·x - 4

5·y - 10 = 3, therefore, y = $\dfrac{13}{5}$

Therefore, the two equations are neither parallel nor perpendicular

Neither

7. The equations are;

2·x + 6·y = -3

Which gives $y = -\dfrac{1}{3} \cdot x - \dfrac{1}{2}$

12·y = 4·x + 20

Which gives

$y = \dfrac{1}{3} \cdot x + \dfrac{5}{3}$

m₁ ≠ m₂

$m_1 \neq -\dfrac{1}{m_2}$

Neither

8. 2·x - 5·y = -3

Which gives; $y = \dfrac{2}{5} \cdot x +\dfrac{3}{5}$

5·x + 27 = 6

$x = -\dfrac{21}{5}$

Therefore, the slopes are not equal, or perpendicular, the correct option is Neither

Learn more here:

brainly.com/question/16732089

6 0

3 years ago

Although five of John's answers were incorrect, 90% of his answers were correct. How many questions did John answer in all?

fiasKO [112]

Answer:

John answered 50 questions.

Step-by-step explanation:

Although five of John's answers were incorrect, 90% of his answers were correct.

This means that 5 is 100 - 90% = 10% of the total number of questions, n. So

$0.1n = 5$

$n = \frac{5}{0.1}$

$n = 50$

John answered 50 questions.

7 0

3 years ago

What is the 3 digit number of the ones period in 288,322,170

AnnZ [28]

Answer:

170

The ones period consists of the ones, tens, and hundreds digits.

6 0

3 years ago

Cole ride his bike for 45 miles at a rate if 15 miles per hour. How long did it take him to ride in 40 miles? PLEASE HELP

tatiyna

15x=45
45/15 =3
X=3
45 miles in 3 hours

How long did it take for 40 miles?

15x=40
40/15 = 2.6666667

15 x 2= 30
15 x 2.5 = 37.5
15 x 2.6 = 39
15 x 2.7 = 40.5
1 hour equals 60 mins

Answer:
It took Cole about 2 hours and 6 mins to ride 40 miles.

5 0

3 years ago