All categories

2 years ago

How much greater than m2+3mn−n2 is 4m2+5mn+6n2? PLEASE HELP

Mathematics

1 answer:

tiny-mole [99]2 years ago

5 0

Answer:

3m² + 2mn + 7n²

Step-by-step explanation:

Subtract m² + 3mn - n² from 4m² + 5mn + 6n², that is

4m² + 5mn + 6n² - (m² + 3mn - n²)

= 4m² + 5mn + 6n² - m² - 3mn + n² ← collect like terms

= 3m² + 2mn + 7n²

You might be interested in

A muffin recipe calls for 3 times as much flour as sugar.

BigorU [14]

f=3s

f = the amount of flour

Hope this helps! :)

7 0

3 years ago

What is the value of the digit 1 in the number 0.413

Akimi4 [234]

.01 is the answer to that or one one hundredth

4 0

3 years ago

Read 2 more answers

Please help me please answer it correctly

Kruka [31]

Answer:

$1,150

Step-by-step explanation:

Step 1: Find the total new members

40 - 10

30 new members

Step 2: Add them to the total

30 + 200

230 total members

Step 3: Find the money earned

230 * 5

$1,150

Answer: $1,150

8 0

3 years ago

What is the relationship between the value of the digit 3 in 4,231 and in the value of the digit 3 in the number 3,421?

leva [86]

Answer:

In 4,231, the value of the digit 3 is 100 times the value of the digit 3 in 3,421.

Step-by-step explanation:

Hope this helps.

5 0

2 years ago

Read 2 more answers

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

3 years ago