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Eva8 [605]
3 years ago
7

How much greater than m2+3mn−n2 is 4m2+5mn+6n2? PLEASE HELP

Mathematics
1 answer:
tiny-mole [99]3 years ago
5 0

Answer:

3m² + 2mn + 7n²

Step-by-step explanation:

Subtract m² + 3mn - n² from 4m² + 5mn + 6n², that is

4m² + 5mn + 6n² - (m² + 3mn - n²)

= 4m² + 5mn + 6n² - m² - 3mn + n² ← collect like terms

= 3m² + 2mn + 7n²


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Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

6 0
3 years ago
Read 2 more answers
1. Find the value of x:<br> (110)<br> (618) 62<br> =<br> 315<br> 68
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Answer:

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Step-by-step explanation:

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2 years ago
The expression 146 ÷ 144 is equal to _____.
natulia [17]

Answer:1.01

Step-by-step explanation:

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3 years ago
The difference between the MDC and the LDC's​
Contact [7]

Answer: MDCs have advanced socially and economically, whereas LDCs are in the early stages of development.

8 0
2 years ago
5. Please write the equation of a line in y=mx+b format. Find the SLOPE first then find the Y-INTERCEPT (b) Your answer​
castortr0y [4]

Answer:

y = \frac{5}{3}x-1

Step-by-step explanation:

Let the equation of the line is,

y = mx + b

Here m = slope of the line

b = y-intercept

Slope of a line passing through two points (x_1,y_1) and (x_2,y_2) is,

m = \frac{y_2-y_1}{x_2-x_1}

From the graph attached,

Since, the given line passes through (0, -1) and (3, 4),

Slope 'm' = \frac{4+1}{3-0}

m = \frac{5}{3}

y - intercept 'b' = -1

Therefore, equation of the line will be,

y = \frac{5}{3}x-1

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3 years ago
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