Answer:
Daughter age = 3 years
Step-by-step explanation:
Let x be the age of the women and y be the age of the daughter.
Given:
After five year the sum of the women and daughter age = 40
![(x+5)+(y+5)=40](https://tex.z-dn.net/?f=%28x%2B5%29%2B%28y%2B5%29%3D40)
At present the sum of the women and daughter age
![x+5+y+5=40](https://tex.z-dn.net/?f=x%2B5%2By%2B5%3D40)
![x+y+10=40](https://tex.z-dn.net/?f=x%2By%2B10%3D40)
![x+y=40-10](https://tex.z-dn.net/?f=x%2By%3D40-10)
--------------(1)
So the sum of the present age is ![x+y=30](https://tex.z-dn.net/?f=x%2By%3D30)
The difference in their present age is 24 years.
![x-y=24](https://tex.z-dn.net/?f=x-y%3D24)
![x=24+y](https://tex.z-dn.net/?f=x%3D24%2By)
Now we substitute x value in equation 1.
![(24+y)+y=30](https://tex.z-dn.net/?f=%2824%2By%29%2By%3D30)
![24+2y=30](https://tex.z-dn.net/?f=24%2B2y%3D30)
![2y=30-24](https://tex.z-dn.net/?f=2y%3D30-24)
![2y=6](https://tex.z-dn.net/?f=2y%3D6)
![y=\frac{6}{2}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B6%7D%7B2%7D)
![y=3\ years](https://tex.z-dn.net/?f=y%3D3%5C%20years)
Therefore, the daughter age is 3 years.
The points in the brackets are on the graph are (0, 2) and (6, 10)
<h3>How to determine if the points in the brackets are on the graph?</h3>
The equation of the line is given as
4x - 3y = -6
The points are given as:
{(0,2),(1,3),(4,7),(6,10)}
Rewrite as
(x, y) = {(0,2),(1,3),(4,7),(6,10)}
Next, we substitute the x and y values in the equation 4x - 3y = -6
So, we have
(0, 2):
4(0) - 3(2) = -6
-6 = -6 ---- true
(1, 3):
4(1) - 3(3) = -6
-5 = -6 ---- false
(4, 7):
4(4) - 3(7) = -6
-5 = -6 ---- false
(6, 10):
4(6) - 3(10) = -6
-6 = -6 ---- true
Hence, the points in the brackets are on the graph are (0, 2) and (6, 10)
Read more about linear equations at:
brainly.com/question/2226590
#SPJ1
Answer:
Choice A)
.
Step-by-step explanation:
What are the changes that would bring
to
?
- Translate
to the left by
unit, and - Stretch
vertically (by a factor greater than
.)
. The choices of
listed here are related to
:
- Choice A)
; - Choice B)
; - Choice C)
; - Choice D)
.
The expression in the braces (for example
as in
) is the independent variable.
To shift a function on a cartesian plane to the left by
units, add
to its independent variable. Think about how
, which is to the left of
, will yield the same function value.
Conversely, to shift a function on a cartesian plane to the right by
units, subtract
from its independent variable.
For example,
is
unit to the left of
. Conversely,
is
unit to the right of
. The new function is to the left of
. Meaning that
should should add
to (rather than subtract
from) the independent variable of
. That rules out choice B) and D).
- Multiplying a function by a number that is greater than one will stretch its graph vertically.
- Multiplying a function by a number that is between zero and one will compress its graph vertically.
- Multiplying a function by a number that is between
and zero will flip its graph about the
-axis. Doing so will also compress the graph vertically. - Multiplying a function by a number that is less than
will flip its graph about the
-axis. Doing so will also stretch the graph vertically.
The graph of
is stretched vertically. However, similarly to the graph of this graph
, the graph of
increases as
increases. In other words, the graph of
isn't flipped about the
-axis.
should have been multiplied by a number that is greater than one. That rules out choice C) and D).
Overall, only choice A) meets the requirements.
Since the plot in the question also came with a couple of gridlines, see if the points
's that are on the graph of
fit into the expression
.
Answer:
Cheyenne has a part-time job at which she gets paid by the hour. The table below shows how much money Cheyenne can earn for working variousCheyenne has a part-time job at which she gets paid by the hour. The table below shows how much money Cheyenne can earn for working various
Step-by-step explanation:
Answer:
![A=64\sqrt{3}\ cm^2](https://tex.z-dn.net/?f=A%3D64%5Csqrt%7B3%7D%5C%20cm%5E2)
Step-by-step explanation:
we know that
An <u><em>equilateral triangle</em></u> has three equal sides and three equal interior angles (each interior angle measure 60 degrees)
so
The perimeter is equal to
![P=3b](https://tex.z-dn.net/?f=P%3D3b)
where
b is the length side of the equilateral triangle
we have
![P=48\ cm](https://tex.z-dn.net/?f=P%3D48%5C%20cm)
substitute
![48=3b](https://tex.z-dn.net/?f=48%3D3b)
solve for b
![b=48/3\\b=16\ cm](https://tex.z-dn.net/?f=b%3D48%2F3%5C%5Cb%3D16%5C%20cm)
Find the area
The formula of area applying the law of sines is equal to
![A=\frac{1}{2}b^2sin(60^o)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29)
substitute the value of b
![A=\frac{1}{2}(16)^2sin(60^o)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%2816%29%5E2sin%2860%5Eo%29)
![sin(60^o)=\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=sin%2860%5Eo%29%3D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
![A=\frac{1}{2}(16)^2(\frac{\sqrt{3}}{2})](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%2816%29%5E2%28%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%29)
![A=64\sqrt{3}\ cm^2](https://tex.z-dn.net/?f=A%3D64%5Csqrt%7B3%7D%5C%20cm%5E2)