Question

The circle described by the equation (x 2)2 + (y + 5)2 = 16 is translated 4 units to the left and 1 unit up. At what point is the center of the image circle located?
(Points : 5)
(-4, 6)

(4, -6)

(-2, -4)

(6, -6)

Answer 1

Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center of the circle.

By comparison, (x - 2)^2 + (y + 5)^2 = 16 has center at point (2, -5).
Translating the circle 4 units to the left and 1 unit up gives a new center at point (2 - 4, -5 + 1) = (-2, -4)