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2 years ago

5

Dan earns £7.80 per hour. How much will he earn for 7 hours work

1 answer:

katen-ka-za [31]2 years ago

6 0

Answer: £54.60

Step-by-step explanation:

7.80 x 7 = £54.60

***If you found my answer helpful, please give me the brainliest. :) ***

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2 years ago

Please help I am failing this class!

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2 years ago

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JulsSmile [24]

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2 years ago

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A soup can has a height of 4 inches and a radius of 2.5 inches. What's the area of

Digiron [165]

Answer:

The lateral surface can be thought of as the crossectional area of the surface integral over dA such that
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2 years ago

If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn

mash [69]

Let $a=\tan A$ and $b=\sin A$ . Then

$m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab$

$\implies m^2-n^2=4\tan A\sin A$

and

$mn=(a+b)(a-b)=a^2-b^2$

$\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}$

The expression under the square root can be rewritten as

$\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)$

Recall that

$\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A$

so that

$\tan^2A-\sin^2A=\sin^2A\tan^2A$

and assuming $\sin A>0$ and $\tan A>0$ , we end up with

$4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A$

so that

$m^2-n^2=4\sqrt{mn}$

as required.

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2 years ago