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Ainat [17]
3 years ago
8

Find the product: Negative StartFraction 4 over 9 EndFraction and Negative StartFraction 3 over 8 EndFraction

Mathematics
2 answers:
kobusy [5.1K]3 years ago
8 0

Answer:

c 1/6

Step-by-step explanation:

been there done that

White raven [17]3 years ago
3 0

Answer:

1/6

Step-by-step explanation:

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Nick makes $50 in 4 hours How much money will he make in 1 hour?​
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$12,5

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What conclusion can be made based on this multiplication problem?
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Step-by-step explanation:

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A factory makes widgets x and gadgets y. Widgets cost $3 and gadgets cost $5 each to make. The boss wants at least 10 widgets an
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3 years ago
According to Scarborough Research, more than 85% of working adults commute by car. Of all U.S. cities, Washington, D.C., and New
tamaranim1 [39]

Answer:

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

Here the population standard deviation (σ) is not provided. So the confidence interval would be computed using the <em>t</em>-distribution.

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) using the <em>t</em>-distribution is:

CI=\bar x\pm t_{\alpha /2,(n-1)}\frac{s}{\sqrt{n}}

Given:

\bar x=27.97\\s=10.04\\n=25\\t_{\alpha /2, (n-1)}=t_{0.01/2, (25-1)}=t_{0.005, 24}=2.797

*Use the <em>t</em>-table for the critical value.

Compute the 99% confidence interval as follows:

CI=27.97\pm 2.797\times\frac{10.04}{\sqrt{25}}\\=27.97\pm5.616\\=(22.354, 33.586)\\\approx(22.35, 33.59)

Thus, the 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

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3 years ago
A watermelon seed is 0.4 cm long how far ould a line of 114 seeds strech in meters
Alexeev081 [22]

it would be 0.456 meters.

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3 years ago
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