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DiKsa [7]
2 years ago
7

For this right triangle drawn on the coordinate plane what calculation could be used to find the length of a C?

Mathematics
2 answers:
Crazy boy [7]2 years ago
6 0

Answer:

AB^2 + BC^2 = AC^2

Step-by-step explanation:

the pythagorean theorem( a^2 + b^2 = c^2) is used to solve for the hypotenuse which in this case is AC

^2 means squared incase you didnt know

hope this helped!

Yuki888 [10]2 years ago
5 0
A^2 + b^2 = c^2 is the equation you use
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Write 24 as a prime factors what is the answer
djverab [1.8K]
Write a number as prime factors means to write the number as a product of numbers, all of which are prime. We start by checking whether the number is divisible by prime numbers, starting from the smallest prime number,2.

let's divide 24 into its factors.

first, it's even, so it must divide by 2

24=2*12

12 is also even, so it must divide by 2:


24=2*12=2*2*6

6 is also even, so it must divide by 2:


24=2*12=2*2*6=2*2*2*3

3 is not even, but it's a prime number.

so the solution is
2*2*2*3



7 0
3 years ago
Read 2 more answers
The triangles are similar.
MrMuchimi
25/5 = 5
and also 
15/3 = 5
so
(3x+ 8)/5 = 4
3x + 8 = 20
3x = 12
  x = 12/3
  x = 4

answer is x = 4
7 0
3 years ago
Read 2 more answers
Slope -3/2 passes through (-4,7)
Kryger [21]

Answer:

5/−1

Step-by-step explanation:

Slope =y2−y1x2−x1

7−2−4−−3

5/−1

8 0
3 years ago
Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6
faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between​ the carrier's highest data speed and the mean of all 50 data​ speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that​ [the difference found in part​ (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the​ carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the​ carrier's highest data speed​ significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0
3 years ago
How to do graphs of quadratic functions ​
Anastaziya [24]

Answer:

The Graph of a Quadratic Function

A quadratic function is a polynomial function of degree 2 which can be written in the general form.

Step-by-step explanation:

Example: Graph: f(x)=−x2−2x+3.

Solution:

Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

f(x)f(0)===−x2−2x+3−(0)2−2(0)+33

The y-intercept is (0,3).

Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

f(x)000x+3x======−x2−2x+3−x2−2x+3x2+2x−3(x+3)(x−1)0−3orx−1x==Set f(x)=0.Multiply both sides by −1.Factor.Set each factor equal to zero.01

Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

x====−b2a−(−2)2(−1)2−2−1

Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2  y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

y−intercept:x−intercepts:Vertex:Extra point:(0,3)(−3,0) and (1,0)(−1,4)(−2,3)

Answer:

4 0
3 years ago
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