Domain is set of all x-values. You are supposed to focus on the x-axis instead.
From the graph, the point starts from x = -5 and ends on x = 5. That means no values would exist after x = 5 or before x = -5.
Hence, the domain starts from -5 to 5.
Answer
Start with the given equation.
P1V1=P2V2
To solve for P2, move anything else on that side to the other side so that P2 is alone.
P1V1=P2V2
P2=P1V1/V2
Wow, what a coincidence, I just learned this at school today!
1. Slope
M= yb-ya/xb-xa
M= 8-4/8-6
M= 4/2
M= 2
2. Y-intercept
Y= mx + b
4 = (2)(6) + b
4 = 12 + b
4 = 12 + b
-12 = - 12 + b
-8 = b
Therefore, the equation is Y = 2x - 8
I would go with answer D here just because it is the only option over 13, and the hypotenuse is always larger than the other sides. Im not positive on the math behind it though tbh.
You could find the surface area using two different methods, but coming out with the same answer.
Method One: This method involves using an equation that helps finding the surface area for a square pyramid.
The equation: A+(1/2)ps=SA; we should break down what the letters stand for. A=Area of the base; the area of the base is 10×10=100 P= perimeter of the base; 10×4=40 S= Slant height;14
Let's put these values into the equation and find the surface area. 100+(1/2)(40)(14)=100+(20)(14)=100+280=380 The surface area is 380 in².
Method Two: The picture below shows how to lay out the square pyramid so you can find the area of each the shapes, then add them up. There are four triangles and a square.
Triangles: We use the equation (1/2)BH; let's plug the values in. 1/2(10)(14)=1/2(140)=70; there are four triangles, so let's multiply by four to find the area of all four of them triangles together. 70×4=280
Square: It's the side length squared. 10²=100; let's add everything together.
The four triangles+the square= the surface area
280+100=380
So, the surface area is 380 in².