Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
Equation of a parabola with vertex at (2, -1) is
y = a(x - 2)^2 - 1
Using the given point: -3 = a(4 - 2)^2 - 1
-2 = a(2)^2
4a = -2
a = -1/2
Therefore, required equation is
y = -1/2(x - 2)^2 - 1
y = -1/2(x^2 - 4x + 4) - 1
y = -1/2x^2 + 2x - 2 - 1
y = -1/2x^2 + 2x - 3
Answer:
2
Step-by-step explanation:
m^2 + 5m - 4
Let m = -6
( -6) ^2 + 5(-6) -4
Exponents first
36 + 5(-6) -4
Then multiply
36 -30 -4
Then subtract
6 -4
2
