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Rashid [163]
2 years ago
6

Using the Pythagorean

Mathematics
2 answers:
ioda2 years ago
5 0
  • No need of getting confused about using Pythagorean theorem. Question is indirectly saying to apply distance formula
  • P(-3,-3)
  • Q(7,6)

\\ \sf\longmapsto PQ=\sqrt{(7+3)^2+(6+3)^2}

\\ \sf\longmapsto PQ=\sqrt{(10)^2+(9)^2}

\\ \sf\longmapsto PQ=\sqrt{100+81}

\\ \sf\longmapsto PQ=\sqrt{181}

\\ \sf\longmapsto PQ\approx 13.4units

miss Akunina [59]2 years ago
4 0

Answer:

  • 13.5 units

Step-by-step explanation:

<u>Use distance formula:</u>

  • d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

<u>Substitute the coordinates:</u>

  • d = \sqrt{(-3-7)^2+(-3-6)^2} =\sqrt{10^2+9^2} =\sqrt{181} =13.5 rounded
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Assume f(x) = g(x). Which of the following pairsof functions may be used to represent theequation 3^x+^2 = 7x + 6?
Aloiza [94]
Functions and equations

We have that:

3^{x+2}^{}=7x+6

Let's name each side of it with f(x) and g(x):

Then, we have that:

\begin{gathered} f(x)=3^{x+2} \\ \text{and} \\ g\mleft(x\mright)=7x+6 \end{gathered}

Then, the answer is C

<h2>Answer: C</h2>

4 0
1 year ago
Plzz help if right i give brainliest
bija089 [108]

Answer:

b. (x+6)(x-6)

Step-by-step explanation:

x^2-36  So to get to this answer you can do two things

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In order to get x^2 you need 2xs that are positive which knocks out c and d

Then to get to -36, you need to multiply a positive 6 and a negative 6

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6 0
3 years ago
Solve the quadratic equation below :<br> 2x^2 + 12x =66
Over [174]

Answer:

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5 0
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Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

                 =\frac{2ab^2\cdot \:5-a^2b^2}{5}

                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

7 0
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8 0
3 years ago
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