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VikaD [51]
3 years ago
6

Sabrina is x years old.

Mathematics
2 answers:
Elan Coil [88]3 years ago
8 0

Answer:

10

Step-by-step explanation:

If Sabrina is 5 & Michael is 7. (5×7=35)

Michael is 7, & he is 3 yrs younger than Meghan, who is 10. And Meghan is twice as old as Sabrina, when Sabrina is 5 (5×2=10).

stellarik [79]3 years ago
8 0

Answer:

Meghan is 10 years old

Step-by-step explanation:

We can write out the information with equations and then combine the information. Then, we can solve for x and hence solve for Meghan's age.

We write our first variable, x. Meghan (m) is twice as old as Sabrina (x). So we write:

m = 2x

Michael (M) is 3 years younger than Meghan. So we write:

M = m - 3

The product (multiplication) of Sabrina's and Michael's age is 35. So we write:

Mx = 35

To solve for x, we can substitute Meghan's age (2x) into the equation for Michael.

M = 2x - 3

Then, we can substitute this for M in the final equation to solve for x. This will be a quadratic so we factorise to solve it:

x(2x - 3) = 35

2x² - 3x = 35

2x² - 3x -35 = 0

(2x - 7)(x - 5) = 0

x = ⁷⁄₂ or 5

we know it is 5 since ⁷⁄₂ does not work and it is not a whole number. Hence:

m = 2(5)

m = 10

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IRINA_888 [86]

Step-by-step explanation:

1 Remove parentheses.

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\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

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3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

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4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

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(−24×2)y

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5 Simplify -24\times 2−24×2 to -48−48.

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3

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2

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6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

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8 Simplify 4+44+4 to 88.

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\frac{-48{y}^{8}{x}^{3}}{3}

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10 Move the negative sign to the left.

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−

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11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

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to 16{y}^{8}{x}^{3}16y

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-16{y}^{8}{x}^{3}

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Done

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