the population of san san Pablo ca is about 33,950 people. ten years ago the population was about 30,000. by what PERCENT did th
1 answer:
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Answer:
(0.6613, 8.3387)
Step-by-step explanation:
Let the heights of men be the first population and the heights of women be the second population. Then
We have ,
,
and
,
,
. The pooled
estimate is given by
The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)
, i.e.,
where is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So
, i.e.,
(0.6613, 8.3387)