Ask question

Ask question

All categories

Natasha_Volkova [10]

3 years ago

6

Solve for angel GLN please help asap, need help

1 answer:

likoan [24]3 years ago

6 0

Answer:

119

Step-by-step explanation:

$\mathrm{Supplementary\:angles\:add\:up\:to}\:180^{\circ }$

$\angle \:GKO \mathrm{\:is\:supplementary\:angle\:of\:} \angle \:KNL$

$\mathrm{So\:}\angle \:GKO+\angle \:KNL=180$

$\angle \:GKO+61=180$

$\angle \:GKO=119$

You might be interested in

The Federal Reserve has set a 10% reserve ratio on all deposits.

ella [17]

Answer: $ 81,000

Step-by-step explanation:

After ACC Spellman Company deposits its $ 100,000 into Itsa Bank, Itsa will have $ 90,000 as maximum allowable amount to loan to company B Bugle since it has to reserve 10% of the $ 100,000 or $ 10,000.

When That There Bank receives the $ 90,000, it can loan out $ 81,000 as a maximum amount and reserve $ 9000 ( 10% of 90,000) .

5 0

3 years ago

Read 2 more answers

A polygon has its vertices at the following points.

seropon [69]

Answer:

isosceles trapezoid

Step-by-step explanation:

1) find the distance of the points

$\sqrt{(x2-x1)^2 + (y2 -y1)^2}$

AB = $\sqrt{(4-2)^2 + (7-5)^2} = \sqrt{4 + 4} = \sqrt{8} = 2 \sqrt{2}$

BC = |7-4| = 3

CD = $\sqrt{(9-7)^2 + (5-7)^2}= \sqrt{4+4} = \sqrt{8} = 2 \sqrt{2}$

AD = |9-2| = 7

2) equation of the line that passes threw BC

y = 7

3) equation of the line that passes threw AD

y = 5

conclusion

the quadrilateral has two parallel sides and two congruent sides, so it is a isosceles trapezoid

3 0

2 years ago

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago

What is greatest to least 7.081 , 7.81 ,7.002 , 7.14

wariber [46]

7.81 then 7.14 then 7.081 then 7.002

8 0

3 years ago

(-4,19) (0,3) whats the slope?

Troyanec [42]

The slope is 16/4 which is 4/1 which can also be 4. So the most simplified is 4

4 0

2 years ago

Read 2 more answers