Ask question

Ask question

All categories

2 years ago

14

6. Find the perimeter of the figure below

1 answer:

liraira [26]2 years ago

3 0

Answer:

26 in.

Step-by-step explanation:

» <u>Concepts</u>

The perimeter for a shape is the total distance around it measured in units. The formula to find the perimeter of a trapezoid is a + b + c + d, where a & b are the bases, and c & d are the lengths of the other sides.

» <u>Solution</u>

Adding up all the sides, we get:

$11+7+4+4$
$18+4+4$
$22+4$
$26$

26 inches

You might be interested in

A solid oblique pyramid has a regular pentagonal base. The base has an edge length of 2.16 ft and an area of 8 ft2. Angle ACB me

choli [55]

Volume of the pyramid:
V = 1/3 · B · h
B = 8 ft²
tan 30° = height / 7√3
1/√3 = height / 7√3
height = 7 ft
V = 1/3 · 8 · 7 = 18.67 ft³ ≈ 19 ft³
Answer : D ) 19 ft³

3 0

3 years ago

Read 2 more answers

Solve for x: 2/3 (x-4) =2x

Scrat [10]

This is most likely the answer

5 0

3 years ago

a weed called the Raindrop Vine is known for growing at a very fast rate it can grow up to 0.75 ft per day how fast in inches pe

kari74 [83]

So we need to convert 0.75 feet to inches.

0.75 feet = 9 inches

Then we divide 9 by how many hours are in a day: 24

9/24 = 0.375

The raindrop vine can grow up to 0.375 inches per hour.

6 0

3 years ago

Read 2 more answers

6y + 2x - 2y - 3x<br> PLEASE HELP ASAP THANK YOU

11Alexandr11 [23.1K]

Answer:

4y-x

Step-by-step explanation:

Combine like-terms.

6y-2y and -3x+2x

Do the Math

4y and -x

4y-x

8 0

3 years ago

When a person is breathing normally the amount of air in their lawns varies sinusoidally. When full Karen’s lungs hold 2.8 L of

makkiz [27]

Answer:

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

Step-by-step explanation:

Let the function of quantity in the lung of air be A(t)

So $A(t) \alpha \sin (\frac{t - \alpha }{k} )$

so, A(t) = Amax sin t + b

A(t) = 2.8t⇒ max

A(t) = 0.6t ⇒ min

max value of A(t) occur when sin(t) = 1

and min value of A(t) = 0

So b = 0.6

and A(max) = 2.2

$A(t) = 2.2\sin \frac{(t)}{k} + 0.6$

at t = 2 sec volume of a is 0.6

So function reduce to

$A(t) = 2.2\sin \frac{(t - 2)}{k} + 0.6$

and t = 5 max value of volume is represent

so,

$\sin \frac{t - \alpha }{k} = 1$

$\frac{t - 2}{k} = \frac{\pi }{2}$ when t = 5

$\frac{6}{\pi } = k$

so the equation becomes

$A(t) = 2.2\sin \frac{(t - 2)\pi }{6} + 0.6$

7 0

3 years ago