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2 years ago

HELP PLS 20 POINTS AKDFNXCVSKDNCXV

Mathematics

1 answer:

marysya [2.9K]2 years ago

4 0

Answer:

my favorite

Step-by-step explanation:

Chicken wings, Chicken wings30

Hotdog and Bologna

Chicken and macaroni

Chillin' wit mah homiiieees

Chicken wings, chicken wings30

Hotdog and bologna

Chicken and macaroni

Chillin'wit mah homiiieees

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The sevth term of a geometric sequence is 108 the eight term is 36 find the common ratio

ValentinkaMS [17]

Answer:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

$\sf t_8=108 \\ \sf t_7=36$

Common difference=d

${:}\longrightarrow$ $\sf d=t_8-t_7$

${:}\longrightarrow$ $\sf d=108-36$

${:}\longrightarrow$ $\sf d=72$

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2 years ago

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AnnyKZ [126]

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3 years ago

Question 7(Multiple Choice Worth 3 points)

Taya2010 [7]

Answer: y = one twelfth(x + 2)2

Step-by-step explanation:

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3 years ago

Shortly after their arrival, Europeans began introducing pigs to the Americas as a source of food. Some escaped, and others were

natka813 [3]

Answer: About 800 thousand

The more accurate value is 807,528 but this is also an approximation.

=======================================================

Work Shown:

$t = \text{number of years since the year 2000}$

$P_0 = \text{population (in millions) in the year 2000}$

$P = P_0(1.2)^t\\\\5 = P_0(1.2)^{10}\\\\5 \approx P_0*6.1917364224\\\\P_0 \approx \frac{5}{6.1917364224}\\\\P_0 \approx 0.80752791444922\\\\P_0 \approx 0.807528\\\\$

That's the rough population of wild pigs (in millions) for the year 2000.

Multiply by $10^6$ to get it in terms of units instead.

$0.807528\times10^6 = 807,528$

There were roughly 800 thousand wild pigs in the year 2000.

7 0

1 year ago

Solve for x please?

Olegator [25]

Answer: A. Less than 0

Step-by-step explanation:

The answer when solving it gives you

x = -1.46557113 which means it is less than 0

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3 years ago