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ahrayia [7]
2 years ago
7

8.A great white shark swims 22 feet below sea level. If the angle of

Mathematics
1 answer:
melomori [17]2 years ago
8 0
A 22 ferry below sea depression from the sailboat
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pentagon [3]

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6 0
3 years ago
Determine which of the four levels of measurement​ (nominal, ordinal,​ interval, ratio) is most appropriate for the data below.
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C I hoC. I think I hope this helps you!
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3 years ago
Samantha has 58 ounces of orange juice that she pours into glasses holding 7 1/4 ounces. How many glasses of orange juice can sh
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8 of them! (I'm pretty sure....)
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3 years ago
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Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

__

The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

__

The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
2(4x - 12) + 3x = 6x + 1<br><br> help!! ahh
Anuta_ua [19.1K]
<span>2(4x - 12) + 3x = 6x + 1

Distribute.

8x - 24 + 3x = 6x + 1

Combine like terms.

11x - 24 = 6x + 1

5x = 25

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</span>
8 0
3 years ago
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