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salantis [7]
2 years ago
14

Name all the quadrilaterals that have the given property. two pairs of parallel sides and all angles congruent rhombus, square r

hombus trapezoid rectangle, square
Mathematics
1 answer:
SSSSS [86.1K]2 years ago
5 0
The answer is square, trapezoid, and a rectangle
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1. Choose the correct answer.
Margaret [11]

Answer:

Equilateral triangle

Step-by-step explanation:

equilateral triangle is a triangle in which all three sides have the same length

6 0
2 years ago
Pre-Calc: Find all the zeros of the function.
uysha [10]

The zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i and the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

<h3>What are polynomial expressions?</h3>

Polynomial expressions are mathematical statements that are represented by variables, coefficients and operators

<h3>How to determine the zeros of the polynomial?</h3>

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Set the equation to 0

So, we have

(5y - 4)(5y + 4)(25y^2 + 16) = 0

Expand the equation

So, we have

5y - 4 = 0, 5y + 4 = 0 and 25y^2 + 16 = 0

This gives

5y = 4, 5y = -4 and 25y^2 = -16

Solve the factors of the equation

So, we have

y = 4/5, y = -4/5 and y = ±4/5√i

Hence, the zeros of the polynomial function are y = 4/5, y = -4/5 and y = ±4/5√i

How to write the polynomial as a product of the linear factors?

In (a), we have

The polynomial equation is given as

f(y) = 625y^4 - 256

Express the terms as an exponent of 4

So, we have

f(y) = (5y)^4 - 4^4

Express the terms as an exponent of 2

So, we have

f(y) = (25y^2)^2 - 16^2

Apply the difference of two squares

So, we have

f(y) = (25y^2 - 16)(25y^2 + 16)

Apply the difference of two squares

So, we have

f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Hence, the polynomial as a product of the linear factors is f(y) = (5y - 4)(5y + 4)(25y^2 + 16)

Read more about polynomial at

brainly.com/question/17517586

#SPJ1

5 0
1 year ago
NEED HELP ASAP ILL GIVE YOU BRAINLIST
lesya [120]

Answer is D  You'll do the diameter squared then you multiply by π

6 0
3 years ago
Read 2 more answers
If one of the zeros of the cubic polynomial x3 + ax2 + bx + c is -1, then what will be the product of the other two zeros?
zhenek [66]

Answer:

The product of the other two zeros is c

Step-by-step explanation:

Let α, β and γ be the zeros of the polynomial x³ + ax² + bx + c. Since one of the zeros is -1, therefore let γ = -1. Hence:

sum of the roots = α + β + γ = -a

-1 + β + γ = -a

β + γ = -a + 1

αβ + αγ + βγ = b

-1(β) + (-1)γ + βγ = b

-β -γ + βγ = b

Also, the product of the zeros is equal to -c, hence:

αβγ = -c

-1(βγ) = -c

βγ = c

Hence the product of the other two zeros is c

6 0
3 years ago
The sum of three integers is 228. The second integer is 1 more than the first, and the third integer is 2 more than the first. W
MaRussiya [10]
Ok so to start, your unknown numbers will ne represented as x. The equation looks like this: x+x+1+x+2=228. You have your unknown number, the number plus one, and the numner plus two. To find the answer you divide 228 by 3. Those numbers are all equal though,so you play around with them until you get 75+75+1+75+2=228
7 0
3 years ago
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