Answer:
The correct answer is B high levels of lactose and high levels of cyclic AMP.
Explanation:
Lac operon contain 3 regulatory genes and 3 structural genes.In presence of lactose the repressor molecule that is encoded by Lac I gene cannot bound to the operator region.
Bacause the lactose interact with the repressor and change its conformation so that it cannot repress the expression of the structural genes of lac operon.
On the other hand cyclic AMP is a positive regulator of lac operon .The interaction of cyclic AMP with the promoter region of lac operon stimulates the binding of RNA polymerase in the promoter region to boost the expression of structural genes of lac operon such as Lac Z,Lac Y and Lac A.
Answer:
Reduced reabsorption of salts and nutrients from the proximal tubule.
Explanation:
The proximal convoluted tubules are the site for reabsorption of the largest amount of solute and water from the filtered fluid. It reabsorbs 65% of water, electrolytes such as Na+ and K+, almost 100% of the filtered glucose and amino acids and other electrolytes such as Ca2+, Mg2+, etc.
The simple cuboidal epithelial cells of the proximal convoluted tubule have a prominent brush border of microvilli on their apical surface. These microvilli serve to increase the surface area for reabsorption and secretion. Destruction of these microvilli would reduce the reabsorption of the above-mentioned salts and nutrients from proximal convoluted tubules.
Answer:
Mutations can create entirely new alleles in a population which changes the allele frequencies of a gene pool.
Phat1 = 9/142
Phat 2 = 5/268
Phat 3 14/410
Test statistics = (Phat 1 - Phat 2) / (Square root of (phat × (1- phat))
times the square root of (1/n1 + 1/n2))
Test statistics = 2.373
P- value = 2× (1- normal cdf (2.373, 0, 1))
= 0.0176
At the level of significance, there is difference between the proportion of drug-resistant wihtin the two states.
