Answer:
1.98% or 2%
Explanation:
In US, 1 out of 10000 people has the disease. So, the frequency of the recessive alleles is 1/10000 = 0.0001
This term is q^2, so now we need to find the q term alone. q= = 0.01
Now, as p+q=1 in HW equations, then p=1-q, in this case p=1-0.01=0.99
So, the next part is determine what percentage is the heterozygous carriers and the heterozigous are in the equation named as 2pq
2pq=> 2(0.01)*(0.99)=0.0198 If we convert it to percentage is 0.0198 * 100= 1.98% aproximate to 2%
I think 3 and 4 are organic
<span>Generally speaking ,karyotyping, can determine the gender of an individual and the presence/
absence of chromosomal defects which could lead to disabilities ,diseases and
problems in the person’s growth and development, as well as the probability
which it could be passed on to the offspring. This is done through the evaluation
of the number, shape, size, and position of the chromosomes within a body cell. </span>
HEYA!!!!
The answer to your question is
Two Indian Cow Breeds are ;
Hallikar
Hariana Cattle
Foreign Breeds:-
Brown Swiss
Hope it helps you.
:)
Answer:
The question is not complete as the options are not given, here are the options gotten from another website.
A) Crest.
B. trough.
C) density.
D) amplitude
The correct option is C.
Density.
Explanation:
This is because density of a particle is measured or define as the mass or weight of a particle divided by it's volume. This is a physical property which is determined through it's mass and volume, it illustrate how particles are closer or tend to move bearer to each other through it's mass and volume.