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jeyben [28]
3 years ago
12

The shed in Stephanie’s back yard has a door that measures 6 feet high and 3 feet wide. Stephanie would like to buy and store a

ladder in the shed diagonally. What is the maximum height, in feet, of a ladder she can buy to fit through the door?
Mathematics
1 answer:
Anarel [89]3 years ago
3 0

Answer:

the answer is 6 ft hope it helps

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use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos^4
Firdavs [7]

The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

= (cos² θ)²

= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

= 1/4 + cos 2θ/4 + 1/8 + cos 4θ/8

= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

#SPJ4

5 0
2 years ago
Help i don’t understand!!!!!!!!!!!!
gogolik [260]
24 because it’s 50 %of them
3 0
3 years ago
Read 2 more answers
The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. an actual conveyor belt can vary from the ideal b
Nastasia [14]
50 + 7/32 = 50 7/32
50 - 7/32 = 49 25/32

answers are :
c.) 49 25/32 < = x < = 50 7/32
e.) |x - 50| < = 7/32
     

8 0
3 years ago
Arc AB is 1/6 of the circumference of a circle. What is The radian measure of the central angle?
Novosadov [1.4K]

Answer:

It’s b pie over 3

Step-by-step explanation:

I just know this I did the work

3 0
3 years ago
Read 2 more answers
I need help on #10
Ede4ka [16]
D = sq.root of((x2 - x1)^2 + (y2 - y1)^2)
sq.root of 13 = sq.root of((x - (-2))^2 + (1 - 3)^2)
= sq.root of((x + 2)^2 + (-2)^2)
= sq.root of (x^2 + 4x + 4 + 4)
= sq.root of (x^2 + 4x + 8)

Now if we square both sides:
x^2 + 4x + 8 = 13
x^2 + 4x - 5 = 0
(x + 5)(x - 1) = 0
x = -5 or x = 1
6 0
3 years ago
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