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nikdorinn [45]
3 years ago
10

2w-y=7w-2 (solve for w) Please show work and only give correct answers. Thank you!

Mathematics
2 answers:
GarryVolchara [31]3 years ago
4 0

Step-by-step explanation:

2<em>w</em> - <em>y</em><em> </em>= 7<em>w</em> - 2

-7<em>w</em> -7<em>w</em>

_______________

-5<em>w</em> - <em>y</em><em> </em>= -2

+ y + y

____________

-5<em>w</em> = -2 + <em>y</em>

____ ______

-5 -5

-  \frac{y}{5}  +  \frac{2}{5}  = w

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

Viefleur [7K]3 years ago
3 0

Answer:

2w - y = 7w - 2

-5w - y = -2

-5w = -2 + y

w = -(y -2)/5

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Answer:

g(h(10)) = 2\sqrt 2

Step-by-step explanation:

Given

g(x) = \sqrt {x - 4

h(x) = 2x - 8

Required

g(h(10))

First, calculate g(h(x))

We have:

g(x) = \sqrt {x - 4

This gives:

g(h(x)) = \sqrt {h(x) - 4

Substitute h(x) = 2x - 8

g(h(x)) = \sqrt {2x - 8 - 4

g(h(x)) = \sqrt {2x - 12

Substitute x = 10

g(h(10)) = \sqrt {2*10 - 12

g(h(10)) = \sqrt {20 - 12

g(h(10)) = \sqrt {8\\

Split

g(h(10)) = \sqrt {4} * \sqrt 2

This gives

g(h(10)) = 2\sqrt 2

8 0
3 years ago
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<h3>consistent independent</h3>

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Find the surface area of a rectangular figure
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Answer:

360ft^2

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4 0
3 years ago
Factor: x2 - 14x = -48
Arturiano [62]

Answer:

x = 12 and 2

Step-by-step explanation:

x^2 - 14x + 48 = 0

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3 0
3 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
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