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SashulF [63]
3 years ago
7

Matrices C and D are shown below C= 2 1 0 0 3 4 0 2 1 D= a b -0.4 0 -0.2 0.8 0 0.4 -0.6 what values of a and b will make the equ

ation CD = l true?
Mathematics
1 answer:
Ksju [112]3 years ago
5 0

The question is incomplete. Here is the complete question

Matrices C and D are shown below:

C=\left[\begin{array}{ccc}2&1&0\\0&3&4\\0&2&1\end{array}\right]     D=\left[\begin{array}{ccc}a&b&-0.4\\0&-0.2&0.8\\0&0.4&-0.6\end{array}\right]

What values of a and b will make the equation CD = I true?

(i) a = 0.5

  b = 0.1

(ii) a = 0.1

    b = 0.5

(iii) a = -0.5

    b = -0.1

Answer: (i) a = 0.5

                  b = 0.1

Step-by-step explanation: <u>Identity</u> <u>Matrix</u> (I) is a n x n square matrix with the number 1 on the main diagonal and 0 everywhere else.

The question asks for multiplication of matrices, i.e.:

\left[\begin{array}{ccc}2&1&0\\0&3&4\\0&2&1\end{array}\right]  .   \left[\begin{array}{ccc}a&b&-0.4\\0&-0.2&0.8\\0&0.4&-0.6\end{array}\right] = \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]

To multiply matrices, the number of columns of the 1st matrix must be the same as the number of rows of the 2nd.

Matrix C is a 3x3 square matrix and so is matrix D, so, values of a and b:

2a=1                           2b-0.2=0

a=\frac{1}{2}                            2b=0.2

a = 0.5                          b=0.1

For the equation CD=I be true, a and b has to be 0.5 and 0.1, respectively.

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