Since 2 croissants = $3 we can work out that 1 croissant = $1.50
Multiply $1.50 by 31 and we get $46.50
Therefore 31 croissants is $46.50
-9 because 2+7=9 so the negative part oh then must be -9
Answer:
(-3, 5) radius- r= 5
Step-by-step explanation:
x^2+6x+y^2-10y=-9
Rewrite ^2+6x+y^2-10y=-9 in the form of the standard circle equation
(x-(-3))^2+(y-5)^2= 5^2
Therefore the circle properties are:
(a, b)=(-3, 5), r= 5
Answer:
This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:
"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"
Where X must be a positive number smaller than one, now we can solve it:
we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:
N = 45*(4/5) = 36
And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:
M = 36*X
now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")
M = 36*(1/2) = 18
So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.
Answer:
All the left numbers of the Ratio go by 8's times tables and all the right numbers go by 5's times tables
Step-by-step explanation:
8x1= 8
8x2 =16
8x3 = 24
5x1= 5
5x2= 10
5x3= 15
Let me know if its right.
